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3 years ago

75 points and I’ll give brainlyist and pleas show work

Mathematics

2 answers:

IRISSAK [1]3 years ago

8 0

Answer:

1. y<-2 2. x≤5 3. 0<23 4. 0 ≤ -1 5. inequality: 3 + (7x) < 24 answer: x<3

Step-by-step explanation:

Ymorist [56]3 years ago

7 0

1. 7 - 6y > 9

7 - 6y > 9

Subtract 7 from both sides

-6y > 19 - 7

Subtract 7 from 19 to get 12

-6y > 12

Divide both sides by -6 (because the 6 is negative, the direction of the inequality is changed)

y < 12/-6

Divide 12 by -6 to get -2

y < -2 (graph this on the number line)

2. 2(x+2) - 3x ≥ -1

2 (x+2) - 3x ≥ -1

Use the distributive property to multiply 2 by x+2

2x + 4 -3x ≥ -1

Combine 2x and -3x to get -x

-x + 4 ≥ -1

Subtract 4 from both sides

-x ≥ -1 - 4

Subtract 4 from -1 to get -5

-x ≥ -5

Divide both sides by -1 (again because the 1 is negative, the direction of the inequality is changed)

x ≤ -5/-1

The fraction can be simplified to 5 by removing both negative signs

x ≤ 5 (graph this on the number line)

You might be interested in

What is 3x3x4/45 does anyone know the answer

MariettaO [177]

Answer:

4/5 or 0.8

Step-by-step explanation:

3*3*4/45

3*3=9

9*4=32

32/45=4/5

Hope it helps ;)

5 0

4 years ago

Read 2 more answers

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

Which sequence is modeled by the graph below? coordinate plane showing the points 1, 2; 2, 2; 3, 2; 4, 2

prisoha [69]

We will start with plotting the x coordinates and y coordinates on the graph

The points 1, 2; 2, 2; 3, 2; 4, 2 have been plotted on the graph which has been attached as an image to the solution.

We can see that the value of y is staying constant (2) for all values of x.

Hence, the points represent the equation y = 2.

6 0

3 years ago

What is the solution of the equation 9^2x=6? Round your answer to the nearest ten-thousandth.

sammy [17]

Answer:

0.4077

Step-by-step explanation:

It's important to use parenthesis to avoid confusion.

9^(2x) = 6

Use exponent properties:

(9^2)^x = 6

81^x = 6

Take log of both sides

ln(81^x) = ln(6)

Use log properties:

x ln(81) = ln(6)

Solve for x:

x = ln(6) / ln(81)

x ≈ 0.4077

4 0

3 years ago

Eliminate 3x+2y=4<br> 8x-3y=-6

laila [671]

Steps:
1. Multiply the first line by 3 and the second by 2
3(3x + 2y= 4)
2(8x -3y=-6)
2. New lines are
9x + 6y= 12
16x + -6y=-12
3. Now add/subtract them
25x + 0= 0
25x=0
4. Divide by 25
X=0

5. To find y, substitute the 0 in the x in one of the equations
9x + 6y= 12
9(0) + 6y= 12
6y= 12
6. Divide by 6, your Y=2
7. X=0, Y=2

7 0

3 years ago