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bezimeni [28]
3 years ago
5

URGENT Perform the indicated operation and simplify the result.

Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

The answer to your question is:  (2a - 1) / 4

Step-by-step explanation:

         \frac{12a^{2} - 3}{2} (2a + 1)^{-2}  ( \frac{6}{(2a +1)^{-1} } \\

        \frac{3(4a^{2} -1)}{2} \frac{1}{(2z + 1)^{2} } (\frac{2a + 1)}{6}

        \frac{3(2a + 1)(2a- 1) (2a + 1)}{12(2a + 1)(2a + 1)}

        \frac{(2a - 1)}{4}

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At a farm the ratio of cows to horses was 9:2. If there were 72 cows at the farm, how many horses were there?
bixtya [17]
Let the no. Of horses be x

9÷2 = 72÷x

X= 144÷9
No. Of horses = 16
4 0
3 years ago
Read 2 more answers
Given the formula a = s2 + 3b - c , find the value of a when s = 7, b = 13 and c = -24.
galben [10]

Answer:

a = 112

Step-by-step explanation:

a =s^{2} +3b-c

Given that,

s = 7

b = 13

c = (-24)

Let's solve for a now.

a =s^{2} +3b-c

a = 7^{2} +3*13-(-24)\\

a=49+39+24\\

a=88+24

a=112

Hope this helps you.

Let me know if you have any other questions :-)

3 0
3 years ago
A rectangular tank has length 4m, width 12m and height 3.5..i. If the tank is filled with water 2/3 of its capacity ,calculate t
ipn [44]

Answer:

The volume of the water in the tank is 112 m³

Step-by-step explanation:

The volume of the rectangular prism V = L × W × H, where

  • L is its length
  • W is its width
  • H is its height

∵ A rectangular tank has a length of 4 m, a width of 12 m, and

   a height of 3.5 m

∴ L = 4 m

∴ W = 12 m

∴ H = 3.5 m

∵ V = L × W × H

∴ The volume of the tank = 4 × 12 × 3.5

∴ The volume of the tank = 168 m³

∵ The tank is filled with water  \frac{2}{3} of its capacity

→ That means the volume of the water is  \frac{2}{3}  the volume of the tank

∵ The volume of the water = \frac{2}{3} the volume of the tank

∴ The volume of the water =  \frac{2}{3} × 168

∴ The volume of the water = 112 m³

∴ The volume of the water in the tank is 112 m³

3 0
3 years ago
3-18 even problems algebra 1 math
Tresset [83]

The answers for problems 13-18 are -9, 8, -2, 5, -2, and 15 after equating the same functions.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

From problems 13 - 18, some functions are shown,

13) h(x) = -7x, h(x) = 63

Equate both the function:

-7x = 63

x = -9

14) t(x) = 3x, t(x) = 24

Equate both the function:

3x = 24

x = 8

15) m(x) = 4x + 15, m(x) = 7

4x + 15 = 7

4x = -8

x = -2

16) 6x - 12 = 18

x = 5

17) 1/2 x - 3 = -4

1/2 x = -1

x = -2

18) j(x) = -4/5 x + 7, j(x) = -5

-4/5 x + 7 = -5

-4/5 x = -12

x = 15

Thus, the answers for problems 13-18 are -9, 8, -2, 5, -2, and 15 after equating the same functions.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

7 0
1 year ago
A truck driver travels at 59 miles per hour. The truck tires have a diameter of 30 inches. What is the angular velocity of the w
Misha Larkins [42]

Answer:

661.4\ rpm

Step-by-step explanation:

we know that

1 mile=63,360 inches

step 1

Find the circumference of the wheels

C=2\pi r

we have

r=30/2=15\ in -----> the radius is half the diameter

substitute

C=2\pi(15)

C=30\pi\ in

assume

\pi =3.14

C=30(3.14)=94.2\ in

Remember that    

The circumference of the wheels represent one revolution

Convert 59 miles per hour to inches per minute

59\ mi/h=59*63,360/60=62,304\ in/min

using proportion find the number of revolutions  

\frac{1}{94.2}\frac{rev}{in}=\frac{x}{62,304}\frac{rev}{in}\\ \\x=62,304/94.2\\ \\x=661.4\ rev

therefore

substitute

62,304\ in/min=661.4\ rev/min=661.4\ rpm

5 0
3 years ago
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