<u>Given</u>:
Given that the diameter of the circle is 10 kilometers.
We need to determine the area of the circle.
<u>Radius of the circle:</u>
The radius of the circle can be determined using the formula,
Substituting d = 10, we get;
Thus, the radius of the circle is 5 kilometers.
<u>Area of the circle:</u>
The area of the circle can be determined using the formula,
Substituting r = 5, we get;
Thus, the area of the circle is 78.5 square kilometers.
[surface area of the square pyramid]=area of the base+4*[area of one lateral triangle]
area of the base=12²----> 144 cm²
area of one lateral triangle=b*h/2
b=12 cm
h=slant height -----> 15 cm
area of one lateral triangle=12*15/2-----> 90 cm²
[surface area of the square pyramid]=144+4*[90]----> 504 cm²
the answer is
the surface area of the square pyramid is 504 cm²
We assume the deformed rails follow a circular curver wherer=radius in metres
Step 1: Express H in terms of rUsing the intersection chord relation, we defineH=maximum height of rail above horizontalthenH(2r-H)=3500^2 => H^2 - 2rH + 3500^2 = 0solve for H H=r-sqrt(r^2-3500^2) =>H= r - sqrt(r^2-12250000) ............(1)
Let x=half of the angle subtended by the chord at the centre.then by the difference of arc and chord:2r(x-sin(x))=0.017 =>2rx-2r(sin(x))=0.017 =>2rx-7000=0.017 =>2rx=7000.017......................(2)together with the simple relation of chord and radius,r*sin(x)=3500 ....................(3)Solve (2) and (3) for r and x to getr=910451.67, x=0.003844256Substitute r in (1) to getH= r - sqrt(r^2-12250000)=910451.67-sqrt(910451.67^2-12250000)=6.7275m
Answer:
a= mc⁴
b= -C⅗
Step-by-step explanation:
it is what it is
