Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or 
a = 1, b = 1, c = -182
or 
or 
or 
or 
or 
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182
Answer: x + 12 = 3x + -22
12 + x = 3x + -22
Reorder the terms:
12 + x = -22 + 3x
Solving
12 + x = -22 + 3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3x' to each side of the equation.
12 + x + -3x = -22 + 3x + -3x
Combine like terms: x + -3x = -2x
12 + -2x = -22 + 3x + -3x
Combine like terms: 3x + -3x = 0
12 + -2x = -22 + 0
12 + -2x = -22
Add '-12' to each side of the equation.
12 + -12 + -2x = -22 + -12
Combine like terms: 12 + -12 = 0
0 + -2x = -22 + -12
-2x = -22 + -12
Combine like terms: -22 + -12 = -34
-2x = -34
Divide each side by '-2'.
x = 17
Simplifying
x = 17
(8*4*2/8*7)^2 x (8^0/7^-3)^3 x 7^-9
Simplify the equations:
(8*4*2/8*7)^2 = (64/56)^2 = (8/7)^2
(8^0/7^-3)^3 = (1/7^-3)^3 = 7^9
Now you have :
(8/7)^2 x 7^9 x 7^-9
Multiply 7^9 x 7^-9 by adding the exponents to get 7^0, which = 1
Now you have:
(8/7)^2 x 1
(8/7)^2 = (8x8) / (7x7) = 64/49
64/49 x 1 = 64/49
Answer:
Step-by-step explanation:
when h(t)=0
-4.9 t²+19.6t=0
4.9t(-t+4)=0
either t=0 or t=4
so domain is 0≤t≤4
for range
h(t)=-4.9t²+19.6t
=-4.9(t²-4t+4-4)
=-4.9(t-2)²+19.6
so range is 0≤h≤19.6
Answer: D
Density= mass/volume
12.9g/8cm3= 1.6 g/cm3
