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shusha [124]
4 years ago
11

Help! pls this is urgent don't mind me

Mathematics
2 answers:
Leviafan [203]4 years ago
5 0
What do you need help with??
Stels [109]4 years ago
4 0

Answer:

hey.

Step-by-step explanation:

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Solve the order of PEMDAS<br> 25-16 divided by 2 to the power of three-5+3
irina [24]
25 - 16 / 2^3 - 5 + 3
Start off by putting 2 to the third power to get 8. Then divide 16 by 8 to get 2. 25-2=23-5=18+3=21
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3 years ago
Trey bought 2 pounds of mixed nuts to serve at a party. According to the packaging, 15% of the mixe
Wittaler [7]
I the the answer is A
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Can you please help me :) you are supposed to use a^2+b^2=c^2 format :) I will give you brainliest
svet-max [94.6K]

Answer:

x = 15

Step-by-step explanation:

8²+b²=17²

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3 years ago
Solve the Quadratic equation using the formula x^2 + 2x - 35 = 0​
UkoKoshka [18]

Answer:

x= 5 and -7

Step-by-step explanation:

x^2+2x-35=0\\x= 5, -7

4 0
3 years ago
10 coupons are given to 20 shoppers in a store. Each shopper can receive at most one coupon. 5 of the shoppers are women and 15
Alina [70]

Answer:

\, {20 \choose 10} - {15 \choose 10}

Step-by-step explanation:

We can find the total amount of ways at least a woman receives a coupon by calculating the total amount of possibilities ot distribute the coupon and substract it to the total amount of possibilities to distribute 10 coupons to the 15 men (this is the complementary case that at least a woman receives a cupon).

- The total amount of possibilities to distribute the coupons among the 20 shoppers is equivalent to the total amount of ways to pick a subset of 10 elements from a set of 20. This is the combinatiorial number of 20 with 10, in other words, \, {20 \choose 10} = \frac{20!}{10!10!} .

- To calculate the total amount of possibilities to distribute the coupons among the 15 men, we need to make the same computation we made above but with a set of 15 elements instead of 20. This gives us  \, {15 \choose 10} = \frac{15!}{10!5!} possibilities.

Therefore, we have \, {20 \choose 10} - {15 \choose 10} possibilities to distribute the coupons so that at least one woman receives a coupon.

I hope that works for you!

3 0
3 years ago
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