Thanks for your question!
First thing we have to do here is take t to the other side by multiplication:
rx + sx = t
Now, group together, x as the GCF:
x(r+s) = t
Now, divide
x = t/(r+s)
Hope this helps!
8.12×10^5
... i got this by taking the first number 8 and then counting the places behind the 8 which would be 5 so than you move the decimal place by 5 so you get 8.12 then you show theirs 5 places behind the 8 by adding the 10^5 so youbget 8.12×10^5
Answer:





Step-by-step explanation:

As both
,
lies in the third quadrant.
In the third quadrant,






Answer:
.
Step-by-step explanation:
It is given that a number, x, rounded to 2 significant figures is 1300.
It is possible if,
1. The value of x is greater than of equal to 1250 and less than or equal to 1300.
i.e.,
...(1)
2. The value of x is greater than of equal to 1300 and less than 1350.
i.e.,
...(2)
On combining (1) and (2), we get

1350 is not included in the error interval for x.
Interval notation is
.
Therefore, the error interval for x is
.
I THINK its 2. :) Hope i'm right.