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tresset_1 [31]
3 years ago
7

(10x+5y)(x-6y) in the simplest form

Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:

10x^{2}-55xy-30y^{2}

Step-by-step explanation:

Gnesinka [82]3 years ago
6 0
10 x 2. Answer is above
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How can this product be simplified 8p(-2p^2+6p-2)
Nikitich [7]

Answer:

-16p³ + 48p² - 16p

Explanation:

In order to simplify the given expression, we need to multiplied 8p with (-2p²+6p-2)

8p*(-2p²+6p-2)

we need to distribute 8p over the brackets or parenthesis.

=8p*(-2p²) + 8p*(6p) + 8p*(-2)

= 8*(-2)*p*p² + 8*6p*p + 8*(-2)* p

= -16p³ + 48p² - 16p

We can't simplify it more, so that's the final answer.

I hope it's help.





8 0
3 years ago
Read 2 more answers
Bertie has just had a big win at the lotterey. He spends 4/5 of his money on a large house. He spends 3/4 of his remaining money
SpyIntel [72]

Answer:

Total money = $30,00,000

Step-by-step explanation:

Given:

4/5 money spend on house

3/4 remaining money spend on luxury yacht

2/3 remaining money spend on trip to space

Remaining $50,000 to charity

Find:

Total money

Computation:

Assume Total money = x

So,

Spend on house = [4x/5]

Spend on luxury yacht = [x-4x/5]3/4 = 3x/20

Spend on trip to space = [x/5-3x/20]2/3 = x/30

Remaining money = x/20 - x/30 = x/60 = $50,000

So,

x/60 = $50,000

x = $300,000

Total money = $30,00,000

7 0
3 years ago
Find the X & Y value
SCORPION-xisa [38]

Answer:

Step-by-step explanation:

x = 72°

y = 61°

8 0
3 years ago
Please help me thx ​
anyanavicka [17]
The answer is Y=1/26x-2
5 0
3 years ago
Read 2 more answers
Assume that 33.4% of people have sleepwalked. Assume that in a random sample of 1459 ​adults, 526 have sleepwalked.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given that  33.4% of people have sleepwalked.

Sample size n =1459

Sample favourable persons = 526

Sample proportion p = \frac{526}{1459} \\=0.361

Sample proportion p is normal for large samples with mean = 0.334 and

std error = \sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.334(1-0.334)}{1459} } \\=0.0123

a) P(526 or more of the 1459 adults have sleepwalked.)

=P(p\geq 0.361)\\=P(Z\geq \frac{0.361-0.334}{0.0123} \\=P(Z\geq 2.20)\\=0.5-0.4861\\=0.0139

b) Yes, because hardly 1.4% is the probability

c) 33.4 is very less compared to the average.  Either sample should be improved representing the population or population mean should be increased accordingly.

7 0
3 years ago
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