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3 years ago

Use the zero product property to find the solutions to the equation 6x^2 – 5x = 56.

Mathematics

2 answers:

frez [133]3 years ago

8 0

Answer:

x = 7/2 or x = -8/3

Step-by-step explanation:

Solve for x over the real numbers:

6 x^2 - 5 x = 56

Divide both sides by 6:

x^2 - (5 x)/6 = 28/3

Add 25/144 to both sides:

x^2 - (5 x)/6 + 25/144 = 1369/144

Write the left hand side as a square:

(x - 5/12)^2 = 1369/144

Take the square root of both sides:

x - 5/12 = 37/12 or x - 5/12 = -37/12

Add 5/12 to both sides:

x = 7/2 or x - 5/12 = -37/12

Add 5/12 to both sides:

Answer: x = 7/2 or x = -8/3

viktelen [127]3 years ago

5 0

Step-by-step explanation:

solving for x

6x²-5x=56

subtract 56 from both sides

6x²-5x-56=0

using middle term break method

factorise (56)(6)=(2*2*2*7)(2*3)

=(2*2*2*2) makes 16 and combining(3*7) makes 21

so we have

=6x²+16x-21x-56=0

taking factors out of first two terms and then other two terms

=>2x(3x+8)-7(3x+8)=0

=>(2x-7)(3x+8)=0

either 2x-7=0 or 3x+8=0

2x=7 or 3x=-8

x=7/2 or x=-8/3

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Using an exponential function, it is found that the Tequesta settlement is 1845 years old.

<h3>What is an exponential function?</h3>

The exponential equation for a decaying amount of a substance is given by:

$A(t) = A(0)e^{-rt}$

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A(0) is the initial value.

r is the decay rate, as a decimal.

Researching on the internet, the half-life of carbon 14 is of 5,730 years, hence A(5730) = 0.5A(0), which we use to find r.

$A(t) = A(0)e^{-rt}$

$0.5A(0) = A(0)e^{-5730r}$

$e^{-5730r} = 0.5$

$\ln{e^{-5730r}} = \ln{0.5}$

$5730r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{5730}$

$r = 0.00012096809$

Hence, the equation is:

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The wood chips were found to contain 80% of the atmospheric carbon-14, hence we have to find t for which A(t) = 0.8A(0).

$A(t) = A(0)e^{-0.00012096809t}$

$0.8A(0) = A(0)e^{-0.00012096809t}$

$e^{-0.00012096809t} = 0.8$

$\ln{e^{-0.00012096809t}} = \ln{0.8}$

$-0.00012096809t = \ln{0.8}$

$t = -\frac{\ln{0.8}}{0.00012096809}$

$t = 1845$

The Tequesta settlement is 1845 years old.

You can learn more about exponential functions at brainly.com/question/25537936

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