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Arlecino [84]
3 years ago
12

Tree diagrams are useful for

Computers and Technology
1 answer:
Yuki888 [10]3 years ago
7 0
Tree Diagrams are useful for Probability since they record all possible outcomes in a clear and uncomplicated manner. 
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Instructions The population of town A is less than the population of town B. However, the population of town A is growing faster
weeeeeb [17]

Answer: The c++ program is given below.

#include <iostream>

using namespace std;

int main() {

float townA, townB, growthA, growthB, populationA, populationB;

    int year=0;    

cout<<"Enter present population of town A : ";

cin >> townA;  

cout<<endl<<"Enter present growth rate of town A : ";

cin >> growthA;

growthA = growthA/100;  

cout<<endl<<"Enter present population of town B : ";

cin >> townB;  

cout<<endl<<"Enter present growth rate of town B : ";

cin >> growthB;

growthB = growthB/100;  

do

{

    populationA = townA + (townA * growthA);

    populationB = townB + (townB * growthB);      

    townA = populationA;

    townB = populationB;      

    year++;      

}while(populationA < populationB);  

cout<<endl<<"After " <<year<< " years, population of town A is "<<populationA << " and population of town B is "<< population<<endl;

return 0;

}

Explanation:

All the variables for population and growth rate are declared with float datatype.

The user inputs the present population of both the towns.

The growth rate entered by the user is the percentage growth.

For example, town A has 10% growth rate as shown in the output image.

The program converts 10% into float as 10/100.

growthA = growthA/100;

growthB = growthB/100;

The above conversion is done to ease the calculations.

The year variable is declared as integer and initialized to 0.

The growth in population is computed in a do-while loop. After each growth is calculated, the year variable is incremented by 1.

The loop continues until population of town A becomes greater than or equal to population of town B as mentioned in the question.

Once the loop discontinues, the final populations of town A and town B and the years needed for this growth is displayed.

The new line is introduced using endl keyword.

The function main has return type int hence, 0 is returned at the end of the program.

6 0
4 years ago
If you were an architect planning on building a large scale Municipal complex what type of engineer would you identify as essent
Daniel [21]

Answer: civil engineer

Explanation:

Based on the information given, the type of engineer that would be identified as essential to the success of the project would be the civil engineer.

Civil engineers are the engineers that are in charge of the planning and overseeing building and infrastructure construction. They plan and monitor constructions involving bridges, road, houses, power plants etc.

3 0
3 years ago
The elements in a string type array will be initialized to ____.?
ivanzaharov [21]
The elements in a string type array will be initialized to "Null".
7 0
4 years ago
Class secretType { public: static int count; static int z; secretType(); secretType(int a); void print(); static void incrementY
ANEK [815]

Answer:

a. secretType mySecret(9)

Explanation:

6 0
3 years ago
A painting company has determined that for every 115 square feet of wall space, one gallon of paint and eight hours of labor wil
Reptile [31]

Answer:

Follows are the code to the given question:

Wallsize = int(input("Enter the size of wall space for painting(in sq ft): "))#defining variable Wallsize for input value  

rate = int(input("Enter the price of the paint(per gallon): $"))#defining variable rate for input value

per_Gallon = Wallsize/115#defining a variable per_Gallon that calculate its value

print("Number of Gallons of paint: ",per_Gallon)#print value with message

total_Hours = per_Gallon * 8#defining a variable total_Hours that calculate its value

print("Hours of labor required: ",total_Hours)#print value with message

paint_Cost = rate * per_Gallon#defining a variable paint_Cost that calculate its value

print("Cost of the paint: $",paint_Cost)#print value with message

labor_Charge = total_Hours * 20#defining a variable labor_Charge that calculate its value

print("Labor charges: $",labor_Charge)#print value with message

total_Cost = paint_Cost + labor_Charge#defining a variable total_Cost that calculate its value

print("Total cost of paint job: $",total_Cost)#print value with message

Output:

Enter the size of wall space for painting(in sq ft): 800

Enter the price of the paint(per gallon): $33

Number of Gallons of paint:  6.956521739130435

Hours of labor required:  55.65217391304348

Cost of the paint: $ 229.56521739130434

Labor charges: $ 1113.0434782608695

Total cost of paint job: $ 1342.6086956521738

Explanation:

Please find the complete question in the attached file.

In this code, the "Wallsize and rate" two variable is defined that is used for input the value from the user-end, after input the value multiple variables"

per_Gallon, total_Hours,paint_Cost, labor_Charge, and total_Cost" is declared, in which it calculates its respective value and prints the value with the message value.

3 0
3 years ago
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