
Given:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19
Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.
Estimate of sample mean

Estimate of sample standard deviation


to 5 decimal places.
Thus, using the normal probability table,





Therefore
The probability that the mean weight is between 125 and 130 lbs
P(125<X<130)=0.0731166-0.0018308
=
0.0712858
First, we'll figure out how many animals there are in total by adding up the cats and the dogs. In this case, we have 33+33=66 total animals. Then we need to figure out what fraction of these 66 animals are dogs:

So half of the animals are dogs. To write that as a percent, we need the fraction to be over 100, so:

50% of the animals are dogs.
Answer:
2262.0646
Step-by-step explanation:
the answer is 2262.0646
The correct answer is $45,000 :)