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kari74 [83]
3 years ago
12

Describe the changes water undergoes as it moves between the earth's bodies of water and atmosphere as part of the hydrologic cy

cle.
Chemistry
2 answers:
sergey [27]3 years ago
6 0

The water in a body of water ( lake, river, ocean, or sea) evaporates into he sky forms into a cloud then falls down back as precipitation( snow, hail, and rain)

d1i1m1o1n [39]3 years ago
5 0
The hydrologic cycle is a continuous cycle where water evaporates and travels into the air and becomes part of a cloud and falls down as precipitation and then evaporates again. Then the cycle repeats in a never ending cycle. 
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There are 3.0 g of NO and 3.0 g of CO reacting. what is the limiting reactant ?
xxTIMURxx [149]

Answer:

NO will be the limiting reagent.

Explanation:

The balanced equation is:

2 NO + 2 CO → N₂ + 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • NO: 2 moles
  • CO: 2 moles
  • N₂: 1 mole
  • CO₂: 2 moles

Being the molar mass of each compound:

  • NO: 30 g/mole
  • CO: 28 g/mole
  • N₂: 28 g/mole
  • CO₂: 44 g/mole

Then by stoichiometry the following quantities of mass participate in each reaction:

  • NO: 2 moles* 30 g/mole= 60 g
  • CO: 2 moles* 28 g/mole= 56 g
  • N₂: 1 mole* 28 g/mole= 28 g
  • CO₂: 2 moles* 44 g/mole= 88 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, you can use a simple rule of three as follows: If 56 grams of CO react with 60 grams of NO, 3 grams of CO react with how much mass of NO?

mass of NO=\frac{3 grams of CO*60 grams of NO}{56 grams of CO}

mass of NO= 3.21 grams

But 3.21 grams of NO are not available, 3 grams are available. Since you have less moles than you need to react with 3 grams of CO, <u><em>NO will be the limiting reagent. </em></u>

<u><em></em></u>

4 0
3 years ago
You have 1.20 x 10 24 molecules of H2O. What is the mass of this sample?
goblinko [34]

Answer:

35.86~g~H_2O

Explanation:

In this case, we have to remember that relationship between the <u>avogadro's number</u> and the "mol" concept:

1~mol=6.023x10^2^3~molcules

With this in mind, we can do the <u>first conversion</u>:

1.20x10^2^4~molecules~of~H_2O\frac{1~mol_H_2O}{6.023x10^2^3~molcules~of~H_2O}=1.99~mol_H_2O

Now, if we calculate the molar mass of H_2O. <u>The atomic mass of O is 16 g/mol and the atomic mass of H is 1 g/mol</u>, so:

(16*1)+(1*2)= 18 g/mol

In other words, 1~mol~H_2O=~18~g~H_2O, so:

1.99~mol_H_2O\frac{18~g~H_2O}{1~mol~H_2O}=35.86~g~H_2O

I hope it helps!

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The answer is 60 km/h..
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Answer to the question provided is b frequency

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True, as it can replace time you might have spent learning what you already know
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