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IgorLugansk [536]
3 years ago
12

On a coordinate plane, square A B C D is shown. Point A is at (3, 4), point B is at (2, negative 2), point C is at (negative 4,

negative 1), and point D is at (negative 3, 5). What is the perimeter of square ABCD? StartRoot 37 EndRoot units 4 StartRoot 37 EndRoot units 28 units 37 units

Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer:

4\sqrt{37}

Step-by-step explanation:

Since the figure is a square, find the length of 1 side and multiply by 4 for perimeter.

Calculate the length of AB using the distance formula.

AB = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(3, 4) and (x₂, y₂ ) = B(2, - 2)

AB = \sqrt{(2-3)^2+(-2-4)^2}

     = \sqrt{(-1)^2+(-6)^2}

     = \sqrt{1+36}

     = \sqrt{37}

Hence

perimeter = 4AB = 4\sqrt{37}

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MariettaO [177]

Answer:

\displaystyle y=-\frac{1}{5}x+\frac{17}{5}

Step-by-step explanation:

<u>Equation of a line</u>

A line can be represented by an equation of the form

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Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

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Two lines with slopes m1 and m2 are perpendicular if:

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The given line has a slope m1=5, thus the slope of our required line is:

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The equation of the line now can be expressed as:

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Operating:

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