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Solnce55 [7]
3 years ago
7

Catie set a glass of hot water and a glass of cold water on the kitchen table and let them sit for one hour. How will the partic

le motion within the glasses change?A.The particles in both glasses will speed up.B.The particles in both glasses will slow down.C.The particles in the hot water will slow down, while the particles in the cold water will speed up.D.The particles in the hot water will speed up, while the particles in the cold water will slow down.
Chemistry
1 answer:
Elis [28]3 years ago
5 0

Answer:

C.The particles in the hot water will slow down, while the particles in the cold water will speed up

Explanation:

Heat causes changes in the molecules of substances when applied to them. The molecules of water, as a case study used in this question, when heated has an increased kinetic energy which causes its particles to move faster i.e. speed up. Also, when water is freezed or cold, it's particles move slower i.e. slow down due to decreased kinetic energy.

Hence, when a hot glass of water and a cold glass of water are placed on a kitchen table for 1 hour, they don't remain in their respective thermal state.

- The hot water (with an increased movement of molecules) begin to cool down, hence, its particles slows down as it gets cold or less hot.

- Likewise, the cold water (with a decreased movement of molecules) begins to get warmer, hence, it particles speedens up as it gets warmer.

Therefore, The particles in the hot water will slow down, while the particles in the cold water will speed up

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3 years ago
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A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83
guapka [62]

Answer:

a. 478.69 K

b. 939.43 cm^{3}

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

V_{o} = 785cm^{3} = 0.000785 m^{3}

T_{o} = 400K

P_{o} = 125 Kpa =  125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 m^{3}⋅Pa⋅K^{-1}⋅mol^{-1}

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5T_{1} - (34980 + 35.5T_{o})]

83.8 = (0.03 × 35.5) (T_{1} - 400K)

83.8 = 1.065 (T_{1}  - 400)

78.69 = (T_{1}  - 400)

T_{1} = 400 + 78.69

T_{1}  = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

V_{1}/T_{1} = V_{o}/T_{o}

V_{1}  =  V_{o}T_{1}/T_{o}

V_{1}   = (785 × 478.69)/400

V_{1}   = 939.43 cm^{3}

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P(V_{1}- V_{o}) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

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3 years ago
What is the angle between two of the nitrogen-hydrogen bonds in the ammonium (NH4+) ion?
Arlecino [84]

Answer:

109° 27'

Explanation:

The ammonium ion is tetrahedral in shape, all the HNH bonds are exactly at the tetrahedral bond angle since there are only bond pairs in the structure and no lone pairs. Recall that lone pairs decrease the bond angke from the ideal value in a tetrahedron due to higher repulsion.

8 0
4 years ago
Which of the following could be considered a scientific method? 01.01 the science of chemistry
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Answer:

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If a bus traveled 20 miles north on a straight path, and then traveled 20 miles back to the starting point, what would the veloc
AleksAgata [21]

<u>Answer:</u>

The velocity of the bus be is 0 miles/second

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Velocity is calculated by the formula:

Velocity =   \frac{\text { Displacement }}{\text { Time }}

Displacement = 20+(-20)=0 \text { miles }

Velocity = \frac{0}{T i m e}=0 \text { miles/second }

Therefore, the velocity of the bus is 0 miles/second

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