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Solnce55 [7]
2 years ago
7

Catie set a glass of hot water and a glass of cold water on the kitchen table and let them sit for one hour. How will the partic

le motion within the glasses change?A.The particles in both glasses will speed up.B.The particles in both glasses will slow down.C.The particles in the hot water will slow down, while the particles in the cold water will speed up.D.The particles in the hot water will speed up, while the particles in the cold water will slow down.
Chemistry
1 answer:
Elis [28]2 years ago
5 0

Answer:

C.The particles in the hot water will slow down, while the particles in the cold water will speed up

Explanation:

Heat causes changes in the molecules of substances when applied to them. The molecules of water, as a case study used in this question, when heated has an increased kinetic energy which causes its particles to move faster i.e. speed up. Also, when water is freezed or cold, it's particles move slower i.e. slow down due to decreased kinetic energy.

Hence, when a hot glass of water and a cold glass of water are placed on a kitchen table for 1 hour, they don't remain in their respective thermal state.

- The hot water (with an increased movement of molecules) begin to cool down, hence, its particles slows down as it gets cold or less hot.

- Likewise, the cold water (with a decreased movement of molecules) begins to get warmer, hence, it particles speedens up as it gets warmer.

Therefore, The particles in the hot water will slow down, while the particles in the cold water will speed up

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In the decomposition reaction, 1 mole of water (mw = 18.015 g/mol) was produced for every mole of cuo (mw = 79.545 g/mol) produc
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Reactives -> Products

CuO and water are products.

I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.

Cu(OH)2 -> CuO + H2O

Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

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Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

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3 0
3 years ago
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Answer:

Q1. C

Q2 and Q3 are correct.

Explanation:

Since F=ma, and the force is a constant,

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Let's check:

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