Answer:
The answer to your question is 144 kg
Explanation:
Data
Q = 8669 kJ
T1 = 75°F
T2 = 195°F
Cp = 0.897 J/(g°C)
m = ?
Formula
Q = mCp(T2 - T1)
Process
1.- Convert temperature to °C
T1 = (75 - 32) / 1.8
= 43/1.8
= 23.9°C
T2 = (195 - 32) / 1.8
= 163/1.8
= 90.6°C
2.- Solve for m
m = Q / Cp(T2 - T1)
3.- Substitution
m = 8669000 / 0.897(90.6 - 23.9)
4.- Simplification
m = 8669000 / 59.83
5.- Result
m = 144893.66 g or 144.9 kg
Answer:
G, but I think that theres more than one answer
Answer: 27.27%
Mass percentage of carbon in carbon dioxide is 4412×100=27. 27%.
D.
The products will have at least 2 Na atoms and 1 O atom.
<h3>Further explanation</h3>
If we refer to the law of mass conservation, which states that
<em>In a closed system, the masses before and after the reaction are the same
</em>
then the number of atoms in the reactance will be the same as the number of atoms in the product
In this problem it is known that Na₂O is one of the reactants so that the product of Na atoms and O atoms will at least equal the number of atoms in the bond, namely 2 Na and 1 O
Like an example of this Na₂O reaction:
Na₂O + H₂O ⇒ 2 NaOH
Na : left =2, right = 2
O : left=2, right = 2
