You must figure out what is 60% of 125
to find the answer all you need to do is multiply 125 by 0.6
Cody completed 75 hours
i hope this helps!!
Answer:
No solution
Step-by-step explanation:
17 is an integer that is in between the integers of 16 and 18
16 and 18 are not consecutive integers.
No solution
By eliminating exponents, the <em>logarithmic</em> expression
is equivalent to the <em>logarithmic</em> expression
.
<h3>How to simplify logarithmic functions</h3>
In this problem we are supposed to eliminate all exponents of a <em>logarithmic</em> function by applying any of the following properties:
- ㏒ x · y = ㏒ x + ㏒ y
- ㏒ x/y = ㏒ x - ㏒ y
- ㏒ yˣ = x · ㏒ y
Now, we proceed to simplify the function:



By eliminating exponents, the <em>logarithmic</em> expression
is equivalent to the <em>logarithmic</em> expression
.
To learn more on logarithms: brainly.com/question/24211708
#SPJ1
Answer:
x=12
Step-by-step explanation:
Answer:
LK=12
Step-by-step explanation:
From the given figure, HI=7 and LH=9, and we know that


(1)
Now, from ΔKHL, we have

and from ΔOKH,





(2)
Also, ΔIKL is similar to ΔOHL, therefore





Using equation (2), we get




Thus, the value of LK is 12.