I need help with number 46 Thankyou

Mathematics

1 answer:

Over [174]3 years ago

8 0

A²+B²=C²
6²+8²=C²
C²=100
C=10
Therefore the length of AB is 10 units

You might be interested in

Kiran says, "I bought 2.5 pounds of red and yellow lentils. Both were $1.80 per pound. I spent a total of $4.05." Write a system

Dmitry_Shevchenko [17]

Answer:

The system of equations is given as:

x + y = 2.5 .... Equation 1

1.8x + 1.8y = 4.05....Equation 2

Step-by-step explanation:

Kiran says, "I bought 2.5 pounds of red and yellow lentils. Both were $1.80 per pound. I spent a total of $4.05

Let

x represent red lentils

y represent yellow lentils.

x + y = 2.5 .... Equation 1

x = 2.5 - y

$1.80 × x + $1.80 × y = $4.05

1.80x + 1.80y = 4.05....Equation 2

The system of equations is given as:

x + y = 2.5 .... Equation 1

1.8x + 1.8y = 4.05....Equation 2

6 0

3 years ago

Harry paid $35 for a tie and $11 for a T-shirt. He gave the cashier a 100-dollar bill. How much change did he receive from the c

Vaselesa [24]

Answer:

Step-by-step explanation: you add 35 and 11 together then subtract 100 by the number you got to get the anwser

4 0

2 years ago

Read 2 more answers

Solve the following equation for the variable a. 2a+b=c-4d

Ipatiy [6.2K]

2a=c-4d-b
a=(c-4d-b)/2

3 0

3 years ago

I will attach a screenshot of the math problem.

Alekssandra [29.7K]

Complete the table for the function y = 0.1^x

The first step: plug values from the left column into the ‘x’ spot in the formula y=0.1^x.

* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).

* 0.1^-1 = 1/0.1 = 10

* 0.1^0 = 1 : (Remember this rule: a^0 = 1)

* 0.1^1 = 0.1

Our list of values: 100, 10, 1, 0.1

Now, we can plug these values into your table:

$\left[\begin{array}{ccc}x&y\\2&10\\1&10\\0&1\\1&0.1\end{array}\right]$

The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]

I hope this helped!