There is a really easy way to find this out I can't really help you so if you just look it up on google you should get your awnser
Answer:

Step-by-step explanation:
The area of the triangle.





No, it is not a perfect cube. A perfect cube is a number that is obtained when you cube an integer. For example, 8 (cube of 2), 27 (cube of 3) and 64 (cube of 4). Since -3 cannot be obtained by cubing an integer, it is not a perfect cube.
Answer:
110.979
Step-by-step explanation:
62.7% * 177 = 0.627 * 177 = 110.979
Divide both sides by -3, and replace
with
. Then

Factorize the quadratic in
to get

which in turn means

But
for all real
, so we can ignore the first solution. This leaves us with

If we allow for any complex solution, then we can continue with the solution we ignored:
