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Levart [38]
3 years ago
7

When it comes to finding the common denominator, do I add or subtract it to the denominator ​

Mathematics
2 answers:
MArishka [77]3 years ago
6 0

Answer:

when you find the common denominators you find the LCM.

Step-by-step explanation:

Aloiza [94]3 years ago
5 0

Answer: Subtract

Step-by-step explanation: Make your denominator equal using the concept of LCM, then subtract the numerators accordingly. Rewrite each fraction to its equivilent fraction with a denominator equal to the LCM=30, then you need to subtract the numberators, but make sure to reduce your answer to the lowest possible term. I hope this helps.

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Solve the system of equations using any method. 2X – Y + Z = – 2, 6X + 3Y – 4Z = 8, – 3X + 2Y +3Z = – 6
krok68 [10]

Answer:

Z = - 2, Y = 0, X = 0

Step-by-step explanation:

2X – Y + Z = – 2

6X + 3Y – 4Z = 8

– 3X + 2Y +3Z = – 6

isolate "X" in the first equation

2X - Y + Z = - 2 => isolate "2X"

2X = - 2 - Z + Y => divide either side by 2

X = - 1 - Z/2 + Y/2

substitute this value of X in the second two equations (applying the substitution method here)

6(- 1 - Z/2 + Y/2) + 3Y - 4Z = 8,

6Y - 7Z - 6 = 8

- 3(- 1 - Z/2 + Y/2) + 2Y +3Z = - 6,

Y + 9Z + 6/2 = - 6

isolate Y in the second equation (6Y - 7Z - 6 = 8) and substitute in the third equation (Y + 9Z + 6/2 = - 6)

6Y - 7Z - 6 = 8 => isolate 6Y

6Y = 14 + 7Z => divide either side by 6

Y = 7Z + 14/6 => substitute in second equation

7Z + 14/6 + 9Z + 6/2 = - 6 => solve for Z

61Z + 50/12 = - 6, Z = - 2

substitute the value of Z into the equations "Y = 7Z + 14/6" and using the value of Y and Z, substitute into "X = - 1 - Z/2 + Y/2"

Y = (7(- 2) + 14)/6 = 0 / 6

= 0

X = - 1 - (- 2)/2 + 0/2 = - 1 - (-1) + 0

= - 1 + 1 + 0 = 0

6 0
3 years ago
During the summer, the population of spring lake is 30,155. During the winter, the population drops down to 13,876. How many peo
aleksley [76]
30,155-13,876=16,279
16,279 people spend on the summer months in spring lake.
3 0
4 years ago
Read 2 more answers
Help me on this plz and thank you
Ghella [55]

By solving for x you get x=6

3 0
3 years ago
Read 2 more answers
Look at the figure shown below:
boyakko [2]

These are the steps, with their explanations and conclusions:


1) Draw two triangles: ΔRSP and ΔQSP.


2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).


3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.


4) The segment SP is common to both ΔRSP and Δ QSP.


5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.


Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q


6 0
3 years ago
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TRUE OR FALSE:<br><br> 16 + 72n = (2 + 9n)(8)
scoray [572]

Answer:

true

Step-by-step explanation:

please see the image I attached of my work

3 0
3 years ago
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