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bazaltina [42]
3 years ago
5

Factor 7a^3+28a^2-35a

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0
7a^3+28a^2-35a =\\ \\=7a(a^2+4a+a-a-5) =\\ \\= 7a(a^2+5a -a-5)=\\ \\=7a[(a(a+5)-(a+5))]=\\ \\=7a(a+5)(a-1)


rosijanka [135]3 years ago
5 0
7a^3+28a^2-35a=7a(a^2+4a-5)=(*)\\ \\-------------------------------\\ \\a^2+4a-5-a^2-a+5a-5=a(a-1)+5(a-1)=(a-1)(a+5)\\ \\-------------------------------\\ \\(*)=7a(a-1)(a+5)
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A bike shop rents bikes for $4.50 per hour, plus a $7.50 insurance charge. For how many hours can Peter rent a bike if he has $3
Mandarinka [93]

Answer:

With $30, Peter can afford 5 hours

Step-by-step explanation:

Given

Insurance Charge = $7.5

Charges = $4.5 per hour

Required

Determine the number of hours $30 can afford

First, we need to determine the equation.

<em>Total Charges = Charges per hour + Insurance Charge</em>

Substitute values for Charges per hour and Insurance Charge

Total Charges = 4.5 per hour + 7.5

Let the number of hours be n;

So,

Total Charges = 4.5n + 7.5

To calculate Peter's; substitute 30 for total charges

30 = 4.5n + 7.5

Subtract 7.5 from both sides

4.5n = 30 - 7.5

4.5n = 22.5

Divide both sides by 4.5

n = \frac{22.5}{4.5}

n = 5

Hence;

<em>With $30, Peter can afford 5 hours</em>

3 0
3 years ago
Nick divides 527 baseball cards evenly into 17 stacks. How many baseball cards are in each stack?
Anton [14]

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31..?

Step-by-step explanation:

517 divided by 27 equals 31

3 0
3 years ago
Can you help me please
nasty-shy [4]
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8 0
2 years ago
What is the solution to the inequality 16x - 70x &lt; 27?
vlada-n [284]

Answer:

16x-70x=-64

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5 0
2 years ago
Read 2 more answers
What is the answer to this question I am really having trouble ??
masya89 [10]
<h3>Answer: Choice B</h3><h3>y = x^2 + 7x + 1</h3>

======================================

Proof:

A quick way to confirm that choice B is the only answer is to eliminate the other non-answers.

If you plugged x = 1 into the equation for choice A, you would get

y = -x^2 + 7x + 1

y = -1^2 + 7(1) + 1

y = -1 + 7 + 1

y = 7

We get a result of 7, but we want 9 to be the actual output. So choice A is out.

-----------

Repeat for choice C. Plug in x = 1

y = x^2 - 7x + 1

y = 1^2 - 7(1) + 1

y = 1 - 7 + 1

y = -5

We can eliminate choice C (since again we want a result of y = 9)

-----------

Finally let's check choice D

y = x^2 - 7x - 1

y = 1^2 - 7(1) - 1

y = 1 - 7 - 1

y= -7

so choice D is off the list as well

-----------

The only thing left is choice B, so it must be the answer. It turns out that plugging x = 1 into this equation leads to y = 9 as shown below

y = x^2 + 7x + 1

y = 1^2 + 7(1) + 1

y = 1 + 7 + 1

y = 9

And the same applies to any other x value in the table (eg: plugging in x = 3 leads to y = 31, etc etc).

3 0
3 years ago
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