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stepladder [879]
3 years ago
12

38- Blank:_____=12c+4+3c

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0

Answer:

38-15c-4

Step-by-step explanation:

38-x=12c+4+3c

38-x=15c+4

x=38-15c-4

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Can somebody please solve this for me and show the work? it doesn't look too hard I'm just dumb.​
lana [24]

Answer:

x = 7

Step-by-step explanation:

  • vertical angles are pairs of opposite angles made by intersecting lines. and they are congruent

x + 16 = 4x - 5

x - 4x = - 5 - 16

- 3x = - 21

- x = - 21/3

- x = - 7

x = 7

hope it helps

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3 years ago
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Step-by-step explanation:

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3 years ago
Find the equation of a line that contains the points (−3,−1) and (−4,−7). Write the equation in slope-intercept form
ikadub [295]

Answer:

  y = -8x -25

Step-by-step explanation:

The 2-point form of the equation of a line is useful when you are given 2 points.

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3 years ago
Ratio Question:
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Answer:

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Step-by-step explanation:

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2 years ago
Read 2 more answers
Evaluate exactly the value of the integral from -1 to 0 (2x^4+8x)^3 (4x^3+4),dx. Include the use of substitution and the antider
ddd [48]
Hello,

Let's be

 z=2x^4+8x \\
dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\

 \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\
= 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}=
\left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648

3 0
3 years ago
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