Answer:
Step-by-step explanation:
You have 3 unknowns: a, b, and c. It's our job to find them algebraically. I'm going to start with the point where x = 0 and y = 7. You'll see why in a minute. Filling in the standard form of a quadratic
using (0, 7):
gives you that c = 7. We will use that value now when we write the next 2 equations. Now the point (-2, 19):
and
so
12 = 4a - 2b
Now for the next point (-1, 12):
and
so
5 = a - b
Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:
12 = 4a - 2b
5 = a - b
Multiply the bottom equation by -4 to get a new system:
12 = 4a - 2b
-20 = -4a + 4b
Add those together to get rid of the a terms and end up with
-8 = 2b so
b = -4
Now we can sub in -4 for b to solve for a. I'm using the second bold type equation to do this:
5 = a - (-4) and
5 = a + 4 so
a = 1 and the equation for the quadratic function is
Answer:
B. 5=5
Step-by-step explanation:
Answer:
<h2>
y = 10x + 4</h2>
Step-by-step explanation:
The equation of a line in slope-intercept form is: y = mx + b, where <em>m</em> is a slope and<em> b</em> is y-intercept.
m = 10
b = 4
So, the equation: y = 10x + 4
Answer:
y=20
Step-by-step explanation:
0.6(y-10)=6
0.6y-6=6
0.6y=6+6
0.6y=12
y=12/0.6
y=20
the mistake is added 10 to both sides
Answer:
Latest time he can leave to be home by a quarter before 5 is 4:13
Step-by-step explanation:
Given Max's trip home takes 32 minutes. we have to find the time at which he can leave to be home by a quarter before 5.
quarter before 5 means 4:45
Max's takes 32 min to come to home so he has to leave 32 minutes before the given time.
Hence, latest time he can leave to be home by a quarter before 5 is 4:45-32 = 4:13
