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Montano1993 [528]
3 years ago
11

Mr. Yang is a doctor who regards video games as an effective means of staying fit. What type of game would he recommend to his p

atients?
A. An advergame
B. A social game
C. And educational game
D. An exergame
Computers and Technology
2 answers:
morpeh [17]3 years ago
8 0

Answer:

D. An exergame

Explanation:

It is because the exercise game is the suitable game to staying fit. For example wii video game able to give the similar experience to outdoor activities such as playing tennis, kick boxing etc.

zhenek [66]3 years ago
6 0

Answer:

D) An exergame

Explanation:

It is an exercise game with several activities that are aimed to exercise, improve, or maintain physical fitness with a planned, repetitive, and structured format. The game features yoga, strength training, aerobics, and balance games. This type of game will enable Mr. Yang patients to stay fit.

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Answer:

The correct answer for the given question is true .

Explanation:

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The following are the function of SQL  

SQL can insert the data into database

it can update the record into database

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We do not use SQL for writing application it is only used to accessing the database  

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Unscramble thr words <br>1.Nsieg Wiev<br>2.Seeathdat ievw​
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Explanation:

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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

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