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AnnyKZ [126]
3 years ago
5

Fill in the missing information. Tim Worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 w

ith a standard deviation of $16.00. What percent of his expense in this category would he expect to fall between $38.60 and $57.80? The z for $38.60 = -. The percent of area associated with $38.60 = % The z for $57.80 = . The percent of area associated with $57.80 = % Adding the two together, the percent of his expenses between $38.60 and $57.80 is %
Mathematics
2 answers:
inna [77]3 years ago
8 0

Answer:

1) .4

2) 15.5

3) .8

4) 28.8

5) 44.3



sleet_krkn [62]3 years ago
4 0
<span>The z for $38.60 = (38.60 - 45)/16 = -0.4
</span>
<span>The percent of area associated with $38.60 = P(z < -0.4) = 0.34458 =34.46%
</span>
<span>The z for $57.80 = (57.8 - 45)/16 = 0.8.
</span>
<span>The percent of area associated with $57.80 = P(z < 0.8) = 0.78814 = 78.81%

</span><span>the percent of his expenses between $38.60 and $57.80 is (78.81 - 34.46) = 44.35%</span>
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A rectangular prism has a length of 11 mm and with a 5 mm. Its height is double its weight. What is the surface area of the pris
kkurt [141]

Answer:

C. 430

Step-by-step explanation:

length: 11

weight: 5

height (double of weight): 10

2 * (5 * 11 + 10 * 11 + 10 * 5)= 430

4 0
3 years ago
3. A boy mixed 500g of sugar and 120g of salt in 106g of lime juice. What will be the
Fed [463]

Answer:

Option C...726 g

Step-by-step explanation:

Mass of;

sugar = 500g

salt = 120g

lime juice = 106g

mass of mixture = sum of its components

= 500g + 120g + 106g

=726 g

6 0
3 years ago
If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

probability=\frac{6 (6)}{270725}

probability=\frac{36}{270725}

probability=0.000133

Thus, the probability of getting two queens and two kings is 0.000133

7 0
3 years ago
Give an indirect proof of the following statement
arlik [135]
Complicated answer.............
3 0
3 years ago
URGENT HELP
Katena32 [7]

Answer:

a = -6

b = 1

Step-by-step explanation:

The gradient of the tangent to the curve y = ax + bx^3, will be:

dy/dx = a + 3bx²

at (2, -4)

dy/dx = a+3b(2)²

dy/dx = a+12b

Since the gradient at the point is 6, then;

a+12b = 6 ....1

Substitute x = 2 and  y = -4 into the original expression

-4 = 2a + 8b

a + 4b = -2 ...2

a+12b = 6 ....1

Subtract

4b - 12b = -2-6

-8b = -8

b = -8/-8

b = 1

Substitute b = 1 into equation 1

Recall from 1 that a+12b = 6

a+12(1) = 6

a = 6 - 12

a = -6

Hence a = -6, b = 1

5 0
3 years ago
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