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Sholpan [36]
3 years ago
5

Please help me thank you

Mathematics
1 answer:
kupik [55]3 years ago
3 0

wow that's a lot ok.

<u>Part A</u>

Margie has a $10 off their total bill.

52.50 - 10 = 42.50

then it says add %6 sale tax of the discounted amount (42.50)

to set it up you do 42.50/? = 6/100 (that's the 6%) you multiply the 42.50 to 6 then divide it by 100

42.50 x 6 = $255

$255 ÷ 100 = 2.55

that means $2.55 is the 6% of tax on the discounted amount. so you add that to the discount. (42.50 + 2.55) which is $45.05 in total if she used that coupon.

<u>Part B</u>

set up the same equation. but this time the top of 100 is 20 and the other side of the fraction is the total bill before all the coupon and tax($52.50)

52.50/? = 20/100

multiply the 52.50 to 20 divide it by 100

52.50 x 20 = 1050 / 100

tip will by $10.50

<u>Part C</u>

add you ax and tip to the 52.50 (I don't know if that includes her coupon but they only said tax and tip..so Idk) that means 52.50 +10.5 +2.55 = 65.55

the friend group has 5 people in it, including margie right. divide the total amount by 5

65.55 ÷ 5 = $13.11

$13.11 is the amount each friends would pay

**again this was only the tax and tip with the original bill($52.50)** if it was including the coupon then add one more step by subtracting the total amount by $10


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The correct option is D) f(x) = x^3 + 2x^2 - 2x - 4 .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x + 4 .

f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 + 2x - 4 .

f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 - 2x^2 - 2x - 4 .

f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0

Now check for other roots as well.

Substitute x=√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0

Substitute x=-√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0

Therefore, the option is correct.

8 0
3 years ago
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