A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>Its slope would be:
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
The equation of a line is
Hence, the equation is 11x +6y - 80 = 0
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1) P= 64 cm, width = x, length = 14 + x
64 = x + x + 14 + x + 14 + x
64 = 4x + 28
4x = 64 - 28
4x = 36
x = 36/ 4
x = 9
AREA = 9 x (9+14)
Area = 9 x 23
Area = 207 cm
2) smaller no. = y, bigger no. = x
x - y = 3
2x+1/2y=36
Next, multiply 2 to first equation and find y:
2x-2y=6
5/2y=30
y = 12
Substitue y to x-y=3 to find x,
x = 15
3) x = pencil, y = pen
5x + 4y = $6.15
8x + 3y = 9.85$
8x + 7y = ?
5x + 4y = 6.15$ multiply both sides by -3
8x + 3y = 9.85$ multiply both sides by 4
-15x + 32x = (-3)*6.15 + 4*9.85
7x = 19.87 multiply both sides by 8/7
8x = (8/7) x 19.87
Add both equations:
32y - 15y = 8x6.15 - 5*9.58
17y = 1.3
y = 91/17) x 1.3
7y = (7/17)x 1.3
8x + 7y = (8/7) x 19.87 + (7/17) x 1.3
8x + 7y = $23.244
4) 2l + 2w = 0
2 x 2l + 2 x 1/2w = 40 + 16
l+w = 20
4l+w = 56
I’ve got l = 12 and w = 8
5) answer: 28.56 feet (approx)
step-by-step explanation:
since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.
we have to find out the measurement of segment ab.
therefore, tan 55° = \frac{ab}{bc}
but bc = 20 feet.
⇒ tan 55 ° = \frac{ab}{20}
⇒ ab = 20 × tan 55 °
⇒ ab = 20 × 1.42814800674
⇒ ab = 28.5629601348 ≈ 28.56 feet
6) The answer is teh attachment !
7) 3x-x+2=4
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