The answer is (-6, 5) for K.
In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Kx + Lx)/2 = Mx
(Kx + 8)/2 = 1
Kx + 8 = 2
Kx = -6
And now we do the same thing for y values
(Ky + Ly)/2 = My
(Ky + -7)/2 = -1
Ky + -7 = -2
Ky = 5
This gives us the final point of (-6, 5)
Your pfp. *kneels down*
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For perpendicular lines, the slopes are negative reciprocals of one another. Therefore, the slope of QC = 3/2
Using this into the formula of slope:
3/2 = (y + 6) / (-1 + 3)
y = -9
If the slope of CD is 2/3, then y works out to be -3.
Answer:
Given that a polynomial has a constant term and at least one other term what is the minimum number of possible zero values based on the rational zero test? a-0 b-2 c-3 d-4