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3 years ago

11

A car velocity change from 26 m/s to 35 m/s in 5 seconds .what it is

1 answer:

ArbitrLikvidat [17]3 years ago

3 0

35-26/5 =29.8 I hope this helps u

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The circumference of the bike tire above is 83.524 inches. What is the radius of the bike tire? (Use 3.14 for .) A. 262.27 in B.

Shtirlitz [24]

Answer:

Option <u>C. 13.3 in</u>.

Step-by-step explanation:

Here's the required formula to find the radius of the bike tire :

$\longrightarrow{\pmb{\sf{C_{(Circle)} = 2\pi r}}}$

C = circumference
π = 3.14
r = radius

Substituting all the given values in the formula to find the radius of the bike tire :

$\begin{gathered} \qquad{\longrightarrow{\sf{C_{(Circle)} = 2\pi r}}} \\ \\ \qquad{\longrightarrow{\sf{83.524 = 2 \times 3.14 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{83.524 = 6.28 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{83.524 = 6.28r}}} \\ \\ \qquad{\longrightarrow{\sf{r = \frac{83.524}{6.28}}}} \\ \\ \qquad{\longrightarrow{\sf{r = 13.3 \: in}}} \\ \\ \qquad \star{\underline{\boxed{\sf{\red{r = 13.3 \: in}}}}}\end{gathered}$

Hence, the radius of bike tire is 13.3 inches.

$\rule{300}{2.5}$

6 0

2 years ago

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If the sum of three consecutive integers is 36, what is the smallest of these integers?

DedPeter [7]

Let the three consecutive equals:
x, x+1, x+2

sum:
x+(x+1)+(x+2) = 36
3x + 3 = 36
x+1 = 36/3
x+1 = 12
x=12-1
x=11

5 0

3 years ago

PLEASEE HELP!! Find the area of the kite.

aev [14]

Answer:

9

Step-by-step explanation:

Area of kite is Area of triangles. Area is 6+3=9

6 0

3 years ago

The difference between twice a number and 16 is 30. Which math statement is an equation that represents this relationship?

AleksAgata [21]

Answer:

D

Step-by-step explanation:

7 0

2 years ago

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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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3 0

1 year ago

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