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3 years ago

11

A car velocity change from 26 m/s to 35 m/s in 5 seconds .what it is

1 answer:

ArbitrLikvidat [17]3 years ago

3 0

35-26/5 =29.8 I hope this helps u

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eric has a riddle: " i am thinking of a fraction that is equivalent to 2/5 and the numerator is 18 less than the denominator." w

dezoksy [38]

Answer:

12/30

Step-by-step explanation:

So we know that the denominator-numerator=18

And we also know that it's equal to 4/10 or 2/5.

Soooooooooooooo the most easiest is just to trial and error: 12/30

But I don't really know the more complex formula...

5 0

3 years ago

What is the equation of the line parallel to x = 7, passing through the point (-4, 1)? A. X = -4 B. X = 1 C. Y = -4 D. Y = 1

77julia77 [94]

Answer:

x=-4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Multiply. (2.5 times 10^-8) (9 times 10^-10)

Lorico [155]

The complete answer is 2.25E-17

but I think it may be A

8 0

3 years ago

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago

to communication companies offer calling plans with company X it cost $0.35 to connect and then $0.05 for each minute with compa

Mama L [17]

Answer:

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

Step-by-step explanation:

Given:

Cost of X company = $\$ 0.35+(\$0.05\times 1 \ minute)$

Cost of Y Company = $\$ 0.15+(\$0.04\times 1 \ minute)$

for n minutes

Cost of X company for n minutes = $\$ 0.35+(\$0.05\times n \ minute)$

Cost of Y Company for n minutes = $\$ 0.15+(\$0.04\times n \ minute)$

Difference for n minutes we get by Subtracting Cost of Y Company for n minutes by Cost of X company for n minutes

Difference for n minutes = $(\$ 0.2+\$ 0.01n)$ = $(0.2+0.01n)\times 10^2 \ cents$

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

6 0

3 years ago