D=-8
3(-8-8)-5 3(-16)-5=-48-5=-53
9(-8+2)+1=9(-6)+1=-54+1=-53
Because both positive and negative values have<span> a positive </span>absolute value.
We are trying to find the number that when added to 19, gives us less than 42. We can set up this simple inequality:
19 + x < 42
Now, subtract 19 from both sides:
x < 23
Our number can be anything less than 23.
Answer:
(3*9)+(3*6)
Step-by-step explanation:
