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stepladder [879]
3 years ago
13

Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydive

r falls 64ft in 2 seconds, how far will he fall in 10 seconds
Mathematics
1 answer:
Firdavs [7]3 years ago
3 0

Answer:

The skydiver will fall 1600 ft in 10 seconds.

Step-by-step explanation:

<u>Distance a body falls from rest varies directly as the squares of the time it falls </u>

Let distance = s    

      time = t

Therefore , s = k \times t^{2}

Given, the body falls 64 ft in 2 seconds.

Substituting in above equation,

64 = k \times (2)^{2}

64 = k \times (4)

 k  = \frac{64}{4}

 k = 16 ft/s^{2}

We have to find how much he will fall in 10 seconds.

s = k \times t^{2}

s = 16 \times 10^{2}

s = 16 \times 100

s = 1600 ft

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