Question

Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydiver falls 64ft in 2 seconds, how far will he fall in 10 seconds

Answer 1

Answer:

The skydiver will fall 1600 ft in 10 seconds.

Step-by-step explanation:

Distance a body falls from rest varies directly as the squares of the time it falls

Let distance = s    

      time = t

Therefore , s = k $\times t^{2}$

Given, the body falls 64 ft in 2 seconds.

Substituting in above equation,

64 = k $\times (2)^{2}$

64 = k $\times (4)$

 k  = $\frac{64}{4}$

 k = 16 ft/$s^{2}$

We have to find how much he will fall in 10 seconds.

s = k $\times t^{2}$

s = $16 \times 10^{2}$

s = $16 \times 100$

s = 1600 ft