3 years ago

Please help ASAP thank u!! :))

Mathematics

1 answer:

frozen [14]3 years ago

6 0

Answer:

Use your brain

Step-by-step explanation:

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3 years ago

A farmer has a truckload of watermelons to take to market. At the beginning of the trip, the watermelons weigh 1000 kg. 99% of t

Mariulka [41]

Answer:

The weight of watermelon at the end of the trip is <u>500 kg.</u>

Step-by-step explanation:

Given:

The weight of watermelons is 1000kg.

At the beginning of the trip watermelon is 99% of the weight:

99% of 1000kg

$\frac{99}{100}\times 1000$

$=0.99\times 1000$

$= 990$ kg

Now, at the end of the trip it is 98% of weight. So, let $x$ kg of water has been evaporated. So, remaining weight of the watermelon is $1000-x$ .

If $x$ kg of water is removed, then the amount of water left is $990-x$ .

As per question, water now weighs 98% of the total weight. So,

98% of ( $1000-x$ ) = $990-x$

$\frac{98}{100}\times (1000-x)=990-x$

$980-0.98x=990-x$

$-0.98x+x=990-980$ (Bringing like terms on one side)

$0.02x=10\\x=\frac{10}{0.02}=500\ kg$

Therefore, the weight of watermelon at the end of the trip is given as:

Weight = $1000 - x$ = 1000 - 500 = 500 kg

Therefore, the watermelon weighs 500 kg at the end of trip.

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