From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)
The answer is:
<span>D. Minimum at (2, 3)</span>
1) 2+12a
2) 8-5x
3)12-3z
i think those are the answers :)
A.
This is because in each circle the lines increase by one, so from the triangle (3 lines) to the rectangle (4 lines) it only makes sense to put a pentagon (5 lines)