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Vlad1618 [11]
3 years ago
14

A Wendy’s fast-food restaurant sells hamburgers and chicken sandwiches. On a typical weekday, the demand for hamburgers is norma

lly distributed with a mean of 450 and standard deviation of 80 and the demand for chicken sandwiches is normally distributed with a mean of 120 and standard deviation of 30. How many hamburgers must the restaurant stock to be 99% sure of not running out on a given day?
Mathematics
1 answer:
Leto [7]3 years ago
5 0
Our given: Hamburgers sold daily are normally distributed and have a mean of 450 and standard deviation of 80 which is denoted by X ~ N (450,80)

What we do not know: How many hamburgers must the restaurant stock so that they won't run out. So let that be X:
Let x: the number of required hamburgers the restaurant needs

Solution:
So our X should be greater than 0.99

P(X>0.99) = 0.99 means
P(Z>(X-450) divided by 80) > 0.99

From the normal distribution table, .99 Z score is = 2.3263

solve for X by:

2.3263 = (X-450) divided by 80
X-450= 80*2.3263 = 186.1
X= 450+186.1=636.1

Answer: 636 hamburgers should be stocked.
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Answer: Phoebe have 48 apples.

Explanation:

It is given that Pru, Piper, and Phoebe share apples in the ratio 5:3:4. If Pru has 24 more apples than Piper.

Let the total number of apples be x.

The sum of the ratios is,

Sum=5+3+4=12

Therefore the number of apples shared by Pru, Piper, Phoebe are \frac{5}{12}x, \frac{3}{12}x,\frac{4}{12}x respectively.

It is given that Pru has 24 more apples than Piper, so

\frac{5}{12}x-\frac{3}{12}x=24

\frac{5-3}{12}x=24

\frac{2}{12}x=24

\frac{1}{6}x=24

x=144

Since phoebe have \frac{4}{12}x appels,

\frac{4}{12}x=\frac{4}{12}\times 144=48

Therefore, Phoebe have 48 apples.

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Step-by-step explanation:

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5. Mark's brother is five years older than Mark.
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9

Step-by-step explanation:

Let's say Mark is M and his brother is B.

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M+M+5=23

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i think so

Step-by-step explanation:

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