Write the coordinates of the vertices of a rectangle whose length and breadth are 5 and 3 unites respectively, one vertex at the
origin, the longer side lies on the x-axis and one of the vertices lies on the third quadrant .
2 answers:
Solution:
As we can see according to the coordinate diagram, the length of the rectangle is 5 unit long in the negative x axis and negative 3 in the y axis, now with one vertex at origin.
Therefore there is 1 vertex that have their y coordinate as zero and other whose x coordinate is 0.
Hence, the value of two vertex that are on line with the axis are (-5, 0) and (0.-3).
To the value of x and y we use the coordinates (-5, 0) and (0, -3), as we can see the value of x axis is -5 and the value of y =3.
Hence, the value of (x, y) = (-5, 3).
And the other coordinates are (-5, 0) , (0,-3) and (0, 0)
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The system is
i)
ii)
The solutions to this system, are all points (x, y) for which BOTH these 2 inequalities hold.
Check the points separately:
(5, 1)
i)
True
ii)
Not True
(0, 0)
i)
True
ii)
True
(-2, -3)
i)
True
ii)
True
(2, 5)
i)
Not True
ii)
Not True
Answer: (0, 0) and (-2, -3)
i)
ii)
The solutions to this system, are all points (x, y) for which BOTH these 2 inequalities hold.
Check the points separately:
(5, 1)
i)
ii)
(0, 0)
i)
ii)
(-2, -3)
i)
ii)
(2, 5)
i)
ii)
Answer: (0, 0) and (-2, -3)
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
