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4 years ago

9th out of 10 questions

Mathematics

2 answers:

Mazyrski [523]4 years ago

8 0

Hello! When dividing fractions, you multiply by the reciprocal of the second fraction. So 2/3 divided by 1/2 would be 2/3 times 2.

As you can see, the first fraction would be the same. Therefore, a will be 4. 5 and 6 will swap, so b will be 6 and c will be 5.

Therefore, our answer is D) a=4, b=6, c=5

I hope this helps!

olya-2409 [2.1K]4 years ago

8 0

The answer is D because,

when you solve the equation, $\frac{1}{4}$ ÷ $\frac{5}{6}$ you get $\frac{3}{10}$

If you distribute the answers in D: a=4, b=6, c=5

you would get, $\frac{1}{4}$ × $\frac{6}{5}$

After solving that you would get $\frac{6}{20}$ and reducing that you would get $\frac{3}{20}$

So, $\frac{3}{20}$ = $\frac{3}{20}$

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Which statement best compares a line and a point ?

jenyasd209 [6]

Hey there!

The answer for your problem is: a line is a set of 2 or more points in a plane

a point is a specific location in a plane

Let me know if you'd like me to explain how I got this answer!

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3 years ago

If A, B, and C are mutually exclusive events with P(A) = 0.2, P(B) = 0.3, and P(C) = 0.4, determine the following probabilities:

fiasKO [112]

a. The events are mutually exclusive, so

$P(A\cup B\cup C)=P(A)+P(B)+P(C)=\boxed{0.9}$

b. For the same reason,

$P(A\cap B\cap C)=\boxed0$

Another way to see this is to use the result from part (a), and the inclusion/exclusion principle:

$P(A\cap B\cap C)=P(A)+P(B)+P(C)-P(A\cup B\cup C)$

and the right side reduces to 0.

c. Same as (b),

$P(A\cap B)=\boxed0$

d. Same as (b),

$P((A\cup B)\cap C)=\boxed0$

We can also use the distributivity rule for unions and intersections to write

$P((A\cup B)\cap C)=P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)=0$

e. If the $A'$ is the complement of $A$ , then by DeMorgan's law,

$P(A'\cap B'\cap C')=P(A\cup B\cup C)'=1-P(A\cup B\cup C)=\boxed{0.1}$

4 0

3 years ago

Chris has a blue coat and a

Tju [1.3M]

Answer: P = 0.125 = 1/8

Step-by-step explanation:

We know that he has a blue coat and a black coat.

If he dresses at random, then the probability of getting the blue coat is equal to the quotient between the number of blue coats (1) and the total number of coats (2).

Then the probability is:

p = 1/2

We also know that he has blue pants and brown pants, the probability of getting at random the blue pants is calculated in the same way than above, then:

q = 1/2

And for the shirt he has a blue shirt and a red one, the probability of randomly selecting the blue one is calculated in the same way than above, then:

k = 1/2

Now, the joint probability (he selects all blue clothes) is equal to the product of the individual probabilities:

P = p*q*k = (1/2)*(1/2)*(1/2) = 1/8 = 0.125

3 0

3 years ago

Can you solve this?? It's, 5x-9y= -2

Andrej [43]

The slope is m= 5/9 sorry if you weren’t looking for the slope

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Valentin [98]

Answer:

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