Factor the following:
12 x^4 - 42 x^3 - 90 x^2
Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)
Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)
Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer: 6 x^2 (2 x + 3) (x - 5)
The question didn't make sense, could you add more to it?
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
The answer would be C, sorry if I’m wrong
For reference, one full circle is 360 degrees or 2pi radians.
If we were to convert 360 degrees to radians, we could set up the following equation:
360k = 2pi
where k is a constant. By solving for k, we can find what value we must multiply any angle in degrees by to get its radian counterpart.
Divide both sides by 360:
k = 2pi/360
Reduce:
k = pi/180
So to convert an angle from degrees to radians, multiply it by pi/180. For example, 120 degrees would be:
120 * pi/180 = 2pi/3 radians
