No solution because everything cancels out
Since g(6)=6, and both functions are continuous, we have:
![\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2Bf%28x%29g%28x%29%5D%20%3D%2045%5C%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2B6f%28x%29%5D%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B9f%28x%29%5D%20%3D%2045%5C%5C%5C%5C9%5Ccdot%20lim_%7Bx%20%5Cto%206%7D%20f%28x%29%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20f%28x%29%3D5)
if a function is continuous at a point c, then

,
that is, in a c ∈ a continuous interval, f(c) and the limit of f as x approaches c are the same.
Thus, since

, f(6) = 5
Answer: 5
Answer:
6x + 2 ( x - 4) = 8 + 4 ( x + 2)
6x + 2x - 8 = 8 + 4x + 8
<em><u>Arranging</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>terms</u></em><em><u> </u></em>
6x + 2x - 4x = 8 +8 - 8
8x - 4x = 8
4x = 8
x = 8/4
x = 2
Supplementary angles add up to 180, so
6x+60+90 = 180 and solve for x
6x= 30
x=5
Answer:
Female=14 male=6
Step-by-step explanation:
Oof this toke long I understand it now, for yesterday you gotta do 6+6+6+6+6=30 this is the male and so you add 14 to 30=44, now comes the important part of solving this problem. For today you gotta add 4 men and 4 women so you do 6+6+6+6=24 now 14+14+14+14=56 and if you add 56+24=80 .