Answer: Hello there!
this type of equations in one dimension (when all the factors are constants) are written as:
h = initial position + initial velocity*t + (acceleration/2)*t^2
First, let's describe the hunter's equation:
We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.
If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:
h = 18 + 1.5t
where t in seconds.
Now, the equation for the ball:
We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)
the equation for the ball is:
h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2
So the system is:
h = 18 + 1.5t
h = 5 +24t - 16.1t^2
so the right answer is A
[1] y = -x + 5
3x + 3•(-x +5) = 10
0 = -5 => NO solution
Answer:
( 1.5, 0)
Step-by-step explanation:
1. Find the coordinates ; in this case (7,-2) and (-4, 2)
2. Plug it into the formula (x1 + x2 ÷ 2 ) , (y1 + y2 ÷ 2)
3. ( 7 + -4 ÷2) = 1.5 And ( -2 + 2 ÷ 2) = 0
4. Therefore, the midpoint is ( 1.5, 0 )
1; 127 mi
2;78
Sorry i did not know the other answers
I hoped this helped
Idk but just divide both of the fraction hope i helped you a little
