3 years ago

Which of the following best describes the equation below? y = -8x - 3

Mathematics

1 answer:

pochemuha3 years ago

3 0

Could we have a photo of the question please

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The product of-2 and the sum of a number and 8

Sunny_sXe [5.5K]

Answer:

$-2(n+8)$

Step-by-step explanation:

n is an unknown number

"the product" means multiplication

and "the sum" is addition

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2 years ago

How many more dogs than cats were over 10 pounds?<br><br> 10<br><br> 30<br><br> 50<br><br> 100

Sholpan [36]

Answer:

30 30 30 30 30 30 30 30

Step-by-step explanation:

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2 years ago

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a wholesaler allows a discount of 25kobo for every 25 naira goods purchased . find the percentage discount allowed.

ZanzabumX [31]

The percentage discount allowed by the wholesaler is 1%

<h3>Percentage</h3>

1 naira = 100 Kobo

25 naira = 25 × 100

= 2500 Kobo

Percentage discount allowed = 25 / 2500 × 100

= 0.01 × 100

= 1%

Therefore, the percentage discount allowed is 1%

Learn more about percentage:

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5 0

1 year ago

If f left parenthesis x right parenthesis equals x squared minus 3 x plus 5 , then f left parenthesis 4 right parenthesis equals

lord [1]

Answer:

f(4) = 9

Step-by-step explanation:

f left parenthesis x right parenthesis equals x squared minus 3 x plus 5

f(x) = x² - 3x + 5

f left parenthesis 4 right parenthesis equals

f(4) =

f(x) = x² - 3x + 5

When x = 4

f(4) = 4² - 3(4) + 5

= 16 - 12 + 5

= 9

f(4) = 9

6 0

2 years ago

To one-one functions g and h are defined as follows.

Andreyy89

Answer:

9
(x-8)/3
-1

Step-by-step explanation:

The inverse function for a set of ordered pairs can be found by swapping the x- and y-coordinates in each pair.

$g^{-1}(-1)=9\qquad\text{from the $g(x)$ ordered pair $(9, -1)$}$

The inverse of a function expressed algebraically can be found by swapping the x- and y-variables and solving for y.

$h^{-1}(x)\qquad\text{is found from }x=h(y)\\\\x=3y+8\\x-8=3y\\\\y=\dfrac{x-8}{3}\\\\\boxed{h^{-1}(x)=\dfrac{x-8}{3}}$

A function of its own inverse returns the original value:

$\boxed{\left(h\circ h^{-1}\right)(-1)=-1}$

6 0

3 years ago