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Leokris [45]
3 years ago
14

The population of a town is currently 32,000 and it is projected to increase by 5% each year. What would be the population in 4

years?
Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0
You would multiply 32,000 x 0.05 = 1,600 so
1,600 x 4 = 6,400
So the population would grow by 6,400 every 4 years.

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A zoo has 2 male lion one sixth of the lion are male lion how many lions are there at the zoo
pishuonlain [190]

If 1/6 of the population of the zoo are males and there are 2 males, then there must be 12 lions in all. 2 males and 10 females.

4 0
2 years ago
185g shared to the ratio of 2:3
Yuliya22 [10]
The smaller share is 2/(2+3)*185 g = 74 g.
The larger share is 185 -74 g = 111 g.
8 0
3 years ago
If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

10x - 11 = 8x + 23

Subtract 8x from both sides

10x - 11 - 8x = 8x + 23 - 8x

2x - 11 = 23

Add 11 to both sides

2x - 11 + 11 = 23 + 11

2x = 34

Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

x = 17

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0
2 years ago
Another Math Question!
Tresset [83]
I did this equation and it’s A
3 0
3 years ago
What is the solution to the equation 5x = 40?
Dima020 [189]
To find X, we can divide 5 into 40.
40 divided by 5 is 8.
Now we can do 5 x 8. That is 40.

X=40

OR we can do it another way.
40 divided by 5 is 8.
Cross out 5 divided by 5.

Now we have 8. Still.
X is 8
7 0
2 years ago
Read 2 more answers
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