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lyudmila [28]
3 years ago
6

Can you please help me with this question ​

Mathematics
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

1. A $28.18

2. D -$4.16

Good luck!

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Rosy has 16 pencils and 24 erasers. She is putting together packets that will havean equal number of pencils and erasers in each
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16 = 2^4

24 = 2^3 \times 3

\text{HCF =}2^3 = 8

Maximum number of packets = 8

16 ÷ 8 = 2
There are 2 pencils in each packet.

24÷8 = 3
There are 3 erasers in each bag.

Rosy can have a maximum of 8 packets. Each packet has 2 pencils and 3 erasers.
5 0
4 years ago
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Where is the center of the largest circle that you could draw inside a given triangle? . A.the point of concurrency of the media
juin [17]

The <em><u>correct answer</u></em> is:

C.the point of concurrency of the angle bisectors of the triangle

Explanation:

The largest circle that can be drawn inside a triangle is called an inscribed circle.  The center of this circle is called the incenter.

The incenter is formed by the intersection of the angle bisectors of all 3 angles in the triangle.

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3 years ago
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Please answer i need help
White raven [17]

Answer:

5-3í

Step-by-step explanation:

Because the root of nine is three, equaling 5-3í

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3 years ago
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Which of the following expressions have a
Yuki888 [10]
A and D i think.(sry this needed to be 20 characters long)
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3 years ago
An agronomist hopes that a new fertilizer she has developed will enable grape growers to increase the yield of each grapevine by
Phoenix [80]

Answer:

Yes. Fertilization increases grape yields by more than 5 pounds.

Step-by-step explanation:

Let f-fertilized and o-old(unfertilized)

#First, we use our data to calculate the standard error:

SE(\bar y_f-\bar y_o)=\sqrt{\frac{s_f^2}{n_f}+\frac{s_o^2}{n_o}}\\\\=\sqrt{\frac{3.7^2}{44}+\frac{3.4^2}{47}}\\\\=0.7464

#State both null and alternative hypothesis:

H_o:\mu_f-\mu_o=0\\\\H_A=\mu_f-\mu_o>0

#We determine our degrees of freedom as 87.02(using R), we now compute the t-value as:

t=\frac{\bar y_f-\bar y_o}{\sqrt{\frac{s_f^2}{n_f}+\frac{s_o^2}{n_o}}}\\\\\\t=\frac{53.4-52.1}{\sqrt{\frac{s_f^2}{n_f}+\frac{s_o^2}{n_o}}}\\\\\\t=\frac{1.3}{0.7464}\\\\t=1.7417\\\\P=P(t_{87.0>1.7417}=1-0.9575=0.0.0425

Since, the p-value is low, we Reject the null hypothesis. The is enough evidence suggesting that grape yields increase by more than 5 pounds than mean yields of  unfertilized grapes.

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4 years ago
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