<span>X^3+6x^2-17x+2-x^3-x^2-11x+36 = </span>5x^2 - 28x + 38
Answer:
z=(x-mu)/o
Step-by-step explanation:
X - Heights of women aged 20 to 29: X is N(64, 2.7)
Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)
a) X=6'=72"
b) Y = 72"
c) 72' women can be taken as very tall but men moderately taller than average
d) Y<5'5" =65"
e) X>73"
Z>
Almost 0% can be taken
f) IQR =Q3-Q1
A)
x^2 - 6x + c = - 5 + c
using a^2 - 2ab + b^2 = (a-b)^2
so
6x = 2 * x * 3
so
c = 9
Answer
c = 9
b)
substitute c = 9
x^2 - 6x + 9 = - 5 + 9
(x - 3)^2 = 4
Answer:
(x - 3)^2 = 4
c) solve for x
(x - 3)^2 = 4
(x - 3)^2 = 2^2
so
x - 3 = 2
x = 5
and
x - 3 = -2
x = 1
Answer: x = 1 , 3
