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Oxana [17]
3 years ago
11

Many income tax systems are calculated using a tiered method. Under certain tax law, the first $100 000 of earning are subject t

o a 35% tax, earnings greater than $100 000 and up to $500 000 are subjects to a 45% tax. Any earnings greater than $500 000 are taxed at 55%. Write a piecewise function that models this situation.
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0
Here is the step by step explaination
Tax = 0.35 * Earnings (Earnings < $100,000)

Tax = 0.35 * $100,000 + 0.45 * (Earnings - $100,000) ($100,000 < Earnings < $500,000)

Tax = 0.35 * $100,000 + 0.45 * $400,000 + 0.55 * (Earnings - $500,000)

(Earnings > $500,000)
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The longer base of a trapezoid is 8 ft. The longer base of a similar trapezoid is 13 ft. The area of the smaller trapezoid is 24
Licemer1 [7]

Answer:

390 ft²

Step-by-step explanation:

The longer base of a trapezoid is 8 ft. The longer base of a similar trapezoid is 13 ft. The area of the smaller trapezoid is 240 ft² What is the area of the larger trapezoid?

We solve the above question using proportion

(Longer base/Area of trapezoid) smaller trapezoid = (Longer base/Area of trapezoid) bigger trapezoid

Let the the Area of the bigger trapezoid = x

Hence,

= 8ft/240ft = 13ft/x ft

Cross Multiply

8ft × x = 240ft × 13ft

x = 240ft² × 12 ft/8 ft

x = 390 ft²

3 0
3 years ago
Which expression is equivalent to is m4?<br> m2+m3<br> m1+m2<br> m1+m3<br> m5+ m6
Airida [17]

Answer: m1+m3

Step-by-step explanation: 1+3=4 and m1+m3 has the same varibles in the expression.

8 0
3 years ago
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
Round to the nearest whole number <br> 863.406
Elan Coil [88]
I wouold be 700 possibl
6 0
3 years ago
Read 2 more answers
Please help me ‼️I am struggling bad <br> (x2+1)(x3-1)
iris [78.8K]

Answer:

26x²+26

Step-by-step explanation:

3 0
3 years ago
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