Answer:
0.29
Step-by-step explanation:
Given :
n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4
P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01
The expected number of defect in a shipment can be obtained using the expected value formula :
Expected value, E(X) = Σx*p(x)
Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)
E(X) = 0.29
Hence, the expected number of defect in shipment is 0.29
legs of the triangles
Each triangle 30-60-90 is:
one leg: 15 ft => short diagonal = 2 * 15ft = 30ft
other leg, x:
tan(30) = 15 / x => x = 15 ft / tan(30) = 25.98 ft
=> long diagonal = 2 * 25.98ft = 51.96 ft
side of the rhoumbus = hypotenuse of one triangle
side of the rhombus = √ [ (15)^2 + (25.98)^2 ] = √(900) = 30 ft
Area of the rhombus:
4 * area of one triangle = 4 [base*height/2] = 4*15*25.98/2 = 779.43 ft^2
The shortest distance accross the garden is equal to the side of the rhombus = 30 ft
Hi there!
• x = - 3
Let's first calculate f(x) and g(x) individually :-
• f(x) = 4x - 7
⇒ 4(- 3) - 7
⇒ - 12 - 7 = - 19

• g(x) = 2x + 4
⇒ 2(- 3) + 4
⇒ - 6 + 4 = - 2

According to th' question :-
f(x) + g(x)
⇒ - 19 + (- 2)
⇒ - 19 - 2
⇒ - 21

~ Hope it helps!
Just add the two equations together.
2b = 18
b = 18/2
b = 9
9 = k + 10
9 - 10 = k
k = - 1
Answer:
250
Step-by-step explanation:
mp=sp+d%of mp
x = 200+20÷100×x
100x-20x = 20000
x= 250