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Maurinko [17]
2 years ago
11

Find the equation,in standard form, of the line passing through the point (2,-3) and (4,2)

Mathematics
2 answers:
VLD [36.1K]2 years ago
8 0

The standard form:

Ax+By=C

The point-slope form:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (2, -3) and (4, 2). Substitute:

m=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}

y-(-3)=\dfrac{5}{2}(x-2)

y+3=\dfrac{5}{2}(x-2)       <em>use distributive property</em>

y+3=\dfrac{5}{2}x-5            <em>multiply both sides by 2</em>

2y+6=5x-10                     <em>subtract 6 from both sides</em>

2y=5x-16         <em>subtract 5x from both sides</em>

-5x+2y=-16          <em>change the signs</em>

\boxed{5x-2y=16}

sukhopar [10]2 years ago
5 0

Answer:

5x - 2y = 16

Step-by-step explanation:

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