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Maurinko [17]
3 years ago
11

Find the equation,in standard form, of the line passing through the point (2,-3) and (4,2)

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0

The standard form:

Ax+By=C

The point-slope form:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (2, -3) and (4, 2). Substitute:

m=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}

y-(-3)=\dfrac{5}{2}(x-2)

y+3=\dfrac{5}{2}(x-2)       <em>use distributive property</em>

y+3=\dfrac{5}{2}x-5            <em>multiply both sides by 2</em>

2y+6=5x-10                     <em>subtract 6 from both sides</em>

2y=5x-16         <em>subtract 5x from both sides</em>

-5x+2y=-16          <em>change the signs</em>

\boxed{5x-2y=16}

sukhopar [10]3 years ago
5 0

Answer:

5x - 2y = 16

Step-by-step explanation:

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You are a contractor and charge $45 for a site visit plus an additional $24 per hour for each hour you spend working at the site
tino4ka555 [31]

Answer:

Equation: 810= (90 + 24y)

y = 30 hours

Step-by-step explanation:

Given:

Site visit = $45 per site

cost per hour worked = $24

for <u>each </u>work site, the total amount of money earned

= site visit fee + cost for working

But the question mentions TWO sites, hence there will be two site visits. Therefore for TWO sites, we have to account for TWO site visit fee.

Therefore for TWO sites, the total amount of money earned

= site 1 visit fee + site 2 visit fee + cost for working

= (2 x site visit fee) +  cost for working  ------ Equation 1

We are further given that we worked y hours at the hourly work rate of $24 per hour.

Hence the cost for working

= y hours x hourly rate

= y   x   $24

= $24y   (substituting this into equation 1 above)

for TWO sites, the total amount of money earned

= (2 x site visit fee) +  cost for working

= (2 x $45) +  $24y

= $90 + $24y

= $(90 + 24y)

We are also given that we have to earn $810 for two sites, hence

810 = 90 + 24y    

810 - 90 = 24y

24y = 720

y = 720/24

y = 30 hours

8 0
3 years ago
13. Solve 32x+3 = 243 for x.
Alika [10]
The Answer should be 7.5 
If you would like me to elaborate, let me know
7 0
3 years ago
Read 2 more answers
The Empirical Rule The following data represent the length of eruption for a random sample of eruptions at the Old Faithful geys
ad-work [718]

Answer:

(a) Sample Standard Deviation approximately to the nearest whole number = 6

(b) The use of Empirical Rule to make any general statements about the length of eruptions is empirical rules tell us about how normal a distribution and gives us an idea of what the final outcome about the length of eruptions is.

(c) The percentage of eruptions that last between 92 and 116 seconds using the empirical rule is 95%

(d) The actual percentage of eruptions that last between 92 and 116 seconds, inclusive is 95.45%

(e) The percentage of eruptions that last less than 98 seconds using the empirical rule is 16%

(f) The actual percentage of eruptions that last less than 98 seconds is 15.866%

Step-by-step explanation:

(a) Determine the sample standard deviation length of eruption.

Express your answer rounded to the nearest whole number.

Step 1

We find the Mean.

Mean = Sum of Terms/Number of Terms

= 90+ 90+ 92+94+ 95+99+99+100+100, 101+ 101+ 101+101+ 102+102+ 102+103+103+ 103+103+103+ 104+ 104+104+105+105+105+ 106+106+107+108+108+108 + 109+ 109+ 110+ 110+110+110+ 110+ 111+ 113+ 116+120/44

= 4582/44

= 104.1363636

Step 2

Sample Standard deviation = √(x - Mean)²/n - 1

=√( 90 - 104.1363636)²+ (90-104.1363636)² + (92 -104.1363636)² ..........)/44 - 1

= √(199.836777 + 199.836777 + 147.2913224+ 102.7458678+ 83.47314049+ 26.3822314+ 26.3822314+ 17.10950413+17.10950413+ 9.836776857+ 9.836776857, 9.836776857+9.836776857+ 4.564049585+ 4.564049585+ 4.564049585+ 1.291322313+ 1.291322313+ 1.291322313+ 1.291322313+ 1.291322313+ 0.01859504133+ 0.01859504133+ 0.01859504133+ 0.7458677685+ 0.7458677685+ 0.7458677685+ 3.473140497+ 3.473140497+ 8.200413225+ 14.92768595+ 14.92768595+ 14.92768595+ 23.65495868+ 23.65495868+ 34.38223141+ 34.38223141+34.38223141+ 34.38223141+ 34.38223141+47.10950414+ 78.56404959+ 140.7458677+ 251.6549586) /43

= √1679.181818/43

= √39.05073996

= 6.249059126

Approximately to the nearest whole number:

Mean = 104

Standard deviation = 6

(b) On the basis of the histogram drawn in Section 3.1, Problem 28, comment on the appropriateness of using the Empirical Rule to make any general statements about the length of eruptions.

The use of Empirical Rule to make any general statements about the length of eruptions is empirical rules tell us about how normal a distribution and gives us an idea of what the final outcome about the length of eruptions is .

(c) Use the Empirical Rule to determine the percentage of eruptions that last between 92 and 116 seconds.

The empirical rule formula states that:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

Mean = 104, Standard deviation = 6

For 68% μ - σ = 104 - 6 = 98, μ + σ = 104 + 6 = 110

For 95% μ – 2σ = 104 -2(6) = 104 - 12 = 92

μ + 2σ = 104 +2(6) = 104 + 12 = 116

Therefore, the percentage of eruptions that last between 92 and 116 seconds is 95%

(d) Determine the actual percentage of eruptions that last between 92 and 116 seconds, inclusive.

We solve for this using z score formula

The formula for calculating a z-score is is z = (x-μ)/σ

where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean = 104, Standard deviation = 6

For x = 92

z = 92 - 104/6

= -2

Probability value from Z-Table:

P(x = 92) = P(z = -2) = 0.02275

For x = 116

z = 92 - 116/6

= 2

Probability value from Z-Table:

P(x = 116) = P(z = 2) = 0.97725

The actual percentage of eruptions that last between 92 and 116 seconds

= P(x = 116) - P(x = 92)

= 0.97725 - 0.02275

= 0.9545

Converting to percentage = 0.9545 × 100

= 95.45%

Therefore, the actual percentage of eruptions that last between 92 and 116 seconds, inclusive is 95.45%

(e) Use the Empirical Rule to determine the percentage of eruptions that last less than 98 seconds

The empirical rule formula:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

For 68% μ - σ = 104 - 6 = 98,

Therefore, 68% of eruptions that last for 98 seconds.

For less than 98 seconds which is the Left hand side of the distribution, it is calculated as

= 100 - 68/2

= 32/2

= 16%

Therefore, the percentage of eruptions that last less than 98 seconds is 16%

(f) Determine the actual percentage of eruptions that last less than 98 seconds.

The formula for calculating a z-score is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

For x = 98

Z score = x - μ/σ

= 98 - 104/6

= -1

Probability value from Z-Table:

P(x ≤ 98) = P(x < 98) = 0.15866

Converting to percentage =

0.15866 × 100

= 15.866%

Therefore, the actual percentage of eruptions that last less than 98 seconds is 15.866%

4 0
3 years ago
What is x equal to ? Link down below.
scZoUnD [109]

Answer:

50

Step-by-step explanation:

Because of supplementary angles that line has to equal to 180

180-75 = 105

so 105 = (2x + 5)

you can subtract 5 from each side and get

100 = (2x)

then divide each side by 2 and you get

x = 50

you can check it by doing (2 x 50 + 5)

2 x 50 = 100 + 5 = 105 + 75 = 180

5 0
3 years ago
Read 2 more answers
Find m2C.<br> D<br> 18<br> С<br> 9<br> B<br> o<br> mZC=
jeka94
Give me the points thanks
3 0
3 years ago
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