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Travka [436]
2 years ago
6

What is the constant difference for a hyperbola with foci (-3.5, 0) and (3.5, 0) and a point on the hyperbola (3. 5, 24)?

Mathematics
1 answer:
OLga [1]2 years ago
8 0
I do not understand the question
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A 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (1.1%, 3.4%
Anton [14]
The point estimate would be 2.25%.

Confidence intervals are centered around a point estimate; that is, the point estimate is in the very middle of the confidence interval.  We can find the point estimate by averaging both ends of the confidence interval together:

(1.1+3.4)/2 = 2.25.
6 0
3 years ago
You have 250,000 In an IRA at the time you retire.You have the option of investing this money in two funds.Fund A pays 1.2% annu
krok68 [10]

Let x be the amount of money, you fund in Fund A and y be the amount of mone yyou fund in Fund B.

1. You have 250,000 In an IRA at the time you retire and want to invest this money into Funds A and B, then

x+y=250,000.

2. Fund A pays 1.2% (as a decimal 1.2% is 0.012) annually, then x\cdot 0.012=0.012x is annual interest income in Fund A.

Fund B pays 6.2% (as a decimal 6.2% is 0.062) annually, then y\cdot 0.062=0.062y is annual interest income in Fund B.

Since Fund A and Fund B produce an annual interest income of $8,000, then

0.012x+0.062y=8,000.

3. Solve the system of equations:

\left\{\begin{array}{l}x+y=250,000\\0.012x+0.062y=8,000.\end{array}\right.

Express x from first equation x=250,000-y and substitute it into the second equation

0.012(250,000-y)+0.062y=8,000.

Multiply this equation by 1000:

12(250,000-y)+62y=8000,000,\\ \\3000,000-12y+62y=8000,000,\\ \\62y-12y=8000,000-3000,000,\\ \\50y=5000,000,\\ \\y=100,000

Then

x=250,000-100,000=150,000.

Answer: you have to fund $150,000 in Fund A and $100,000 in Fund B.


8 0
2 years ago
19. Using clay, a student made a right circular cone of height 48cm and base
aev [14]

Answer:

fhgiignngmtotmtjfntktngigmtkgitmrjrnrkr28395027

Step-by-step explanation:

jejf ygm no fmfijfpnfimf

3 0
2 years ago
A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
4 0
2 years ago
PLS HELP THIS IS A TEST
Pie

Answer:

D: 7

Step-by-step explanation:

1.75 (7) + 4.50

12.25 + 4.50

= 16.75

16.75 < 20

8 0
3 years ago
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