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3 years ago

Help, algebra 1, thanks plzz

Mathematics

1 answer:

RideAnS [48]3 years ago

6 0

Answer:

9) x = gy/c, 11) a = np/m

Step-by-step explanation:

9) g = xc/y

g*y/c = xc/y *y/c

gy/c = x

11) am = np

am/m = np/m

a = np/m

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Prove the identity

Troyanec [42]

Answer:

Proved

Step-by-step explanation:

The options are not given. So, I will solve from scratch

Given

$\frac{secx-1}{tan x}= \frac{tanx}{secx+1}$

Required

Prove

Multiply the right-hand side by $\frac{secx + 1}{secx + 1}$

$\frac{secx-1}{tan x} * \frac{secx + 1}{secx + 1}= \frac{tanx}{secx+1}$

Apply difference of two squares on the numerator

$\frac{sec^2 x - 1}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}$

In trigonometry:

$tan^2x = sec^2x - 1$

So, we have:

$\frac{tan^2 x}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}$

$\frac{tan x * tan x}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}$

tan x cancels out

$\frac{tan x}{secx + 1} =\frac{tanx}{secx+1}$

<em>Proved</em>

3 0

3 years ago

Pls help !!!!

Nuetrik [128]

Answer:

At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The red ant's distance from the anthill is $a\sqrt{2}$ . The black ant's coordinates may be written as (-a, -a) and the black ant's distance from the anthill is $a\sqrt{2}$ . This shows that at any given moment, both ants are $a\sqrt{2}$ units from the anthill.

Step-by-step explanation:

Given:

red ant's coordinates written as (a,a)

black ant's coordinates are written as (-a, -a)

To find:

The distance of red and black ants from anthill

Solution:

Compute the distance of red ant from the anthill using distance formula

d (red ant) = $\sqrt{(a-0)^{2}+ (a-0)^{2}}$

= $\sqrt{a^{2} + a^{2} }$

= $\sqrt{2a^{2} }$

= $a\sqrt{2}$

So distance of red ant from anthill is $a\sqrt{2}$

Compute the distance of black ant from the anthill using distance formula

d (black ant) = $\sqrt{(-a-0)^{2}+ (-a-0)^{2}}$

= $\sqrt{(-a)^{2} + (-a)^{2} }$

= $\sqrt{a^{2} + a^{2} }$

= $\sqrt{2a^{2} }$

= $a\sqrt{2}$

So distance of black ant from anthill is $a\sqrt{2}$

Hence both ants are $a\sqrt{2}$ units from the anthill.

4 0

3 years ago

This recipe makes four portions of soup.

Harman [31]

Answer:

you need 1/4 of each listed ingredient

Step-by-step explanation:

divide each measurement by 4

7 0

3 years ago

Jane Martin-Smith and her husband deposited $500 in an account on their wedding day and each subsequent anniversary. The money w

PolarNik [594]

Answer:

On their 25th anniversary, their account will have $850

Step-by-step explanation:

7% per year for 25 years is 170%

170% of 500 is 850

I hope this helps!

8 0

3 years ago

Read 2 more answers

Factor 15x^3-6x^2-25x+10 by grouping

Lostsunrise [7]

Answer: (5x-2)(3^2-5)

Step-by-step explanation:

So using the commutative property, we can change the equation 15x^3-6x^2-25x+10 into 15x^3-25x -6x^2+10

Let’s split that into two sections so it’s easier to see:

(15x^3-25x) - (6x^2+10)

Next let’s look at what 15x^3 and -25x have in common. They have 5x in common.

Factoring out 5x, we get this: 5x(3^2-5)

Next let’s look at what -6x^2and 10 have in common. They only have 2 in common, so we factor out 2.

2(-3^2+5) we can write this as -2(3^2-5)

So the end result will be : 5x(3^2-5)-2(3^2-5)

And the complete factorization will be (5x-2)(3^2-5)

7 0

4 years ago