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3 years ago

Paul makes 3 5/6 dozen cookies. He gives each of his friends 1/6 dozen cookies.

1 answer:

7 0

If he gives ALL of the cookies away..

3 5/6 = 6/6 + 6/6 + 6/6 + 5/6

6+6+6+5 = 23

Paul has 23 friends. (if he takes 1/6, then he has 22)

hope this helps

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Tan y+cot y= sec y x csc y prove the identity (y is the variable)

adell [148]

Answer:

Step-by-step explanation:

tany+coty =

$\frac{siny}{cosy} + \frac{cosy}{siny}$ ·

$\frac{sin^{2}y + cos^{2}y }{cosysiny}$

$\frac{1}{cosysiny}$

$(secy) (cscy)$

3 0

3 years ago

Three consecutive integers add up to -36. What are the integers?

nasty-shy [4]

Answer:

We know our answer is correct because 11 + 12 + 13 equals 36 as displayed Below

Explanation

3X + 3 = 36 3X + 3 - 3 = 36 - 3 3X = 33 3X/3 = 33/3 X = 11 Which means that the first number is 11, the second number is 11 + 1 and the third number is 11 + 2. Therefore, three consecutive integers that add up to 36 are 11, 12, and 13. 11 + 12 + 13 = 36 We know our answer is correct because 11 + 12 + 13 equals 36 as displayed above. Therefore, three consecutive integers that add up to 36 are 11, 12, and 13. 11 + 12 + 13 = 36

Plz mark brainliest if helps Also hope helps:)

4 0

2 years ago

ALGEBRA EQUATION PLEASE HELP ASAP -3=12y-5(2y-7)

Dovator [93]

Simplify:

−3=12y−5(2y−7)

−3=12y+(−5)(2y)+(−5)(−7)(Distribute)

−3=12y+−10y+35

−3=(12y+−10y)+(35)(Combine Like Terms)

−3=2y+35

Flip the equation.

2y+35=−3

Subtract 35 from both sides.

2y+35−35=−3−35

2y=−38

Divide both sides by 2.

2y/2=−38/2

y=−19

3 0

3 years ago

Read 2 more answers

Given: ABC , BD is an altitude to side AC, & D is a midpoint Prove: AB BC

Over [174]

Answer:

steps below

Step-by-step explanation:

BD⊥AC ∠ADB = ∠CDB = 90°

D is mid-point: AD = CD

BD = BD

ΔADB ≅ ΔCDB

AB = BC

5 0

2 years ago

Read 2 more answers

Which coordinate lies in the solution set for

tatyana61 [14]

Answer:

Step-by-step explanation:

to do this, u would just sub ur answer choices into the inequalities and see what is true. Keeping in mind, that ur point has to satisfy both inequalities for it to be a solution.

2x + y < 12...subbing in (3,3) 3x - 2y > 2...subbing in (3,3)

2(3) + 3 < 12 3(3) - 2(3) > 2

6 + 3 < 12 9 - 6 > 2

9 < 12....true 3 > 2....true

(3,3) lies in the solution set <==

7 0

3 years ago