Answer:
To prove:
X+Y.Z=(X+Y).(X+Z)
Taking R.H.S
= (X+Y).(X+Z)
By distributive law
= X.X+X.Z+X.Y+Y.Z --- (1)
From Boolean algebra
X.X = X
X.Y+X.Z = X.(Y+Z)
Using these in (1)
=X+X(Y+Z)+Y.Z
=X(1+(Y+Z)+Y.Z --- (2)
As we know (1+X) = 1
Then (2) becomes
=X.1+Y.Z
=X+Y.Z
Which is equal to R.H.S
Hence proved,
X+Y.Z=(X+Y).(X+Z)
100p? if you would like to explain what the variable p is i could help out
The subtrahend is 9 and the difference is 8 and the minuend is 17
Answer:
The answer is <u>54.6</u>.
9.1(6)+8.7(7)=<u>54.6</u>+60.9
Step-by-step explanation:
Given:
9.1(6)+8.7(7)=_+60.9
Now, to solve it:
9.1(6)+8.7(7)=_+60.9
Let the _be x.
So, we remove parenthesis first that makes it multiply with the number next to it:


Now adding on L.H.S:

Subtracting on both sides by 60.9 we get:


Therefore, the answer is 54.6.
The answer is negative 5 because you subtract 12 from each side to get 5x=-25 and -25 divided by 5 is negative 5