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Yuri [45]
3 years ago
13

Please solve 3.4-2.8d+2.8d-1.3

Mathematics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

2.1

Step-by-step explanation:

3.4-2.8d+2.8d-1.3

3.4-1.3=2.1

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Plz help me!!! it is due tomorrow!!!!
AlekseyPX
X is less then or equal to 8
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Which list is in order from least to greatest?  (PS you will see it is more organized once you click on the question)
Studentka2010 [4]
I don't understand the way you put the answeres because 58 is the largest number here yet its before .78 on f and g on plus the number occurs 2 times
4 0
3 years ago
A+B= -7 and AXB= -15
ZanzabumX [31]
A+b=-7
ab=-15

a=-7-b
b(-7-b)=-15

a=-7-b
-b^2-7b+15=0

a=-7-b
b^2+7b-15=0

a=-7-b
b=(-7±sqrt(109))/2
1) 
a=-7-b
b=(-7+sqrt(109))/2

b=(-7+sqrt(109))/2
a=-7+3.5-sqrt(109)/2

b=(-7+sqrt(109))/2
a=-3.5-sqrt(109)/2

2)
a=-7-b
b=(-7-sqrt(109))/2

b=(-7-sqrt(109))/2
a=-7+3.5+sqrt(109)/2

b=(-7-sqrt(109))/2
a=-3.5+sqrt(109)/2
7 0
4 years ago
Fiona has 212 stickers to put in her sticker book. Each page holds 18 stickers. How many pages does Fiona need for all of her st
iVinArrow [24]

Answer:


Step-by-step explanation:

18 stickers------1 page

212 stickers------x pages

For this we can write equation like that:

18*X = 212*1

18x=212

X=11.7777= It means Fiona needs 12 pages for using all these stickes.

4 0
4 years ago
the figure below is a square . Find the length of side x in simplest radical form with a rational denominator.
wel

Answer:

\sqrt{14}

Step-by-step explanation:

In any square with side length s, the diagonal of the square is equal to s\sqrt{2}. Since the side length of this square is \sqrt{7}, the diagonal is equal to \sqrt{7}\cdot \sqrt{2}=\boxed{\sqrt{14}}.

Alternatively, you can form two 45-45-90 triangles with the diagonal of the square. The diagonal acts as the hypotenuse for the both these triangles, and the legs of both triangles are equal to the side length of the square. To find the length of the diagonal, use the Pythagorean Theorem, which states a^2+b^2=c^2, where c is the hypotenuse of the triangle, and a and b are the two legs of the triangle.

In this question, both legs are equal to \sqrt{7}, and we're solving for the diagonal, which is the hypotenuse in this case:

\sqrt{7}^2+\sqrt{7}^2=c^2,\\c^2=14,\\c=\boxed{\sqrt{14}}

4 0
3 years ago
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