1 one and 58 hundredths.
I hope you like this answer, and have a good night and life! :D
You would use PEMDAS
But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57
Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57
Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57
Now you can add all of the numbers together
32➕504=536
536➕57=593
Your answer is 593
Hope this helps! :3
Answer: Integer
Step-by-step explanation: The answer would be integer
Answer:
1&a 2&b 3&c 4&d
Step-by-step explanation:
...
Answer B
Why is because Box B is near the 8 and goes on while Box A only is near 8 and stops there
