All categories

3 years ago

How many 3/4 foot pieces of string can be cut from a 6 foot piece of string?

Mathematics

2 answers:

geniusboy [140]3 years ago

7 0

Answer:

Step-by-step explanation:

6/1 divided by 3/4

6/1*4/3

24/3=8

Law Incorporation [45]3 years ago

4 0

Answer:

$\frac{1}{8}$

Step-by-step explanation:

Divide 3/4 and 6, which will show many pieces can be cut. If you multiplied, it would combine both 3/4 and 6. If you subtracted you will take 3/4 from the 6 feet. If you added you would add on 3/4 on to the 6 feet.

Keep $\frac{3}{4\\}$ . Change the division to multiplication. Flip the 6 to $\frac{1}{6}$ .

Now multiply it out straight.

$\frac{3}{4\\}$ × $\frac{6}{1}$

$\frac{3}{4\\}$ × $\frac{1}{6}$

3×1=3

4×6=24

$\frac{3}{24} =\frac{1}{8}$

You might be interested in

Eight more than the product of some number cubed and two

Greeley [361]

8+ the product of 2 and a number to the third power, what it means 2×m cubed. So it is 8+2m (cubed)

4 0

2 years ago

Simplify the expression 10-4x(6+5-1) divided by 8+7

Eddi Din [679]

Simple,

writing out the problem...

$\frac{10-4x(6+5-1)}{15}$

Simplify it...

-4x(6+5-1)

-4x(11-1)

-4x(10)

-40x

Making it look like...

$\frac{10-40x}{15}$

Cancel out the common factors...

Thus making the answer:

$- \frac{2(4x-1)}{3}$ .

8 0

2 years ago

The exchange rate of 2 USD to Euros is 1.8. How many Euros is $34 USD? Round to 1 decimal place.

tensa zangetsu [6.8K]

Answer:

30.6 euros

Step-by-step explanation:

Set up a proportion: 2/1.8=34/x

2x=61.2

x=30.6

Therefore, 30.6 euros

I hope this helped and have a good rest of your day!

5 0

2 years ago

Which congruence criteria is met in the following scenario?

Arisa [49]

None because the triangles have different lines

7 0

1 year ago

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacemen

mamaluj [8]

<h2>Answer:</h2>

(a)

The probability is : 1/2

(b)

The probability is : 1/2

<h2>Step-by-step explanation:</h2>

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2) (1,3) (1,4) (1,5)

(2,1) (2,3) (2,4) (2,5)

(3,1) (3,2) (3,4) (3,5)

(4,1) (4,2) (4,3) (4,5)

(5,1) (5,2) (5,3) (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

We know that it could be calculated by using the formula:

$P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is: (4,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( since, the only outcome out of 20 outcomes is: (3,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

7 0

2 years ago