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Vanyuwa [196]
3 years ago
11

If 25⋅26=n, then which division equation is also true?

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

9514 1404 393

Answer:

  n÷26=25

Step-by-step explanation:

Starting with the equation ...

  25·26 = n

you can divide both sides of it by 26 to get ...

  25 = n ÷ 26 . . . . matches choice A

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250 squared to the nearest tenth
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3 years ago
Jordan is stacking 2 boxes on a shelf. The bottom box measures 7 inches​ long, 6 inches​ wide, and 6 inches high. The top box is
Andre45 [30]
Answer: 377

Explanation: Length x width x height
7x6 = 42 x 6 = 252
A cube means all sides a equal. So 5x5x5 = 125
Add both together and you get 377 cubic inches.
4 0
3 years ago
Can someone check my answer if I am incorrect please answer this question please answer this question correctly and please show
Elena-2011 [213]

Answer:

2 + (-7) = (-5)

Step-by-step explanation:

Correct problem and method of solving, just miscounted!

It should be + (-7) instead of + (-6).

This also changes the answer to (-5) instead of (-4).

4 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
What is 25 divided by 225
daser333 [38]
0.097- or it could be 0.10 if you round it
5 0
3 years ago
Read 2 more answers
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