Get it in form 4P(y-k)=(x-h)^2
add 8y to both sides
x^2-6x+49=8y
complete the square
-6/3=-3, (-3)^2=9
(x^2-6x+9)+40=8y
(x-3)^2+40=8y
minus 40 both sides
(x-3)^2=8y-40
undistribute 8 on right side
(x-3)^2=(y-5)8
4P(y-k)=(x-h)^2
4(2)(y-5)=(x-3)^2
(h,k) is center
p is distance from vertex to directix and also from vertex to focus
p=2
vertex=(3,5)
in that form, the prabola opens up so
directix is 2 below vertex
focus is 2 above vertex
up and down is y so
5-2=3
5+2=7
directix is y=3
focus=(3,7)
vertex=(3,5)
Answer:
x/5 i thing i am not even sure good luck
Step-by-step explanation:
Answer:
First blank is cos(h)cos(x)
Second blank is sin(x)
Step-by-step explanation:
Look up the identity and apply it here
Square root of 5x+1=6
square root each side
5x+1=6 squared
5x+1=36
subtract 1 on both sides
5x=35
divide both sides by 5
x=7
