Answer:
Reactant : A combustion of hydrocarbon.
Explanation:
It is known that when hydrocarbons are involved in combustion, they produce carbon dioxide and water.
CxHy + (x+y/4)O2 ===> xCO2 + y/2H2O
Solution:
By the following ways the polar molecule doesn’t mix with non-polar molecule
Polar molecules have a portion of their molecule which, relative to the rest of the molecule, is more negative.
Water, for example, has a bent, or V-shape, due to the 2 lone electron pairs on oxygen. This makes the oxygen end more negative than the hydrogen end. This negative area allows for hydrogen bonding between that molecule and other molecules which are also polar.
Non-polar molecules don't have a portion of the molecule which is more negative than the rest. An example of this is a hydrocarbon, like butane. Because there is no relatively negative region to the molecule, it cannot partake in hydrogen bonding and therefore does not mix with polar molecules.
Thus we can conclude that Polar mixes with polar; non-polar mixes with non-polar.
Answer:
The unknown substance is Au ( gold)
Explanation:
SiO2 has a high melting point, is insoluble in water but is a very poor conductor. So the statements do not apply here.
F2 is soluble in water, has a melting point way lower than 1064 °C, and isa gas. F2 doesn't apply here.
Au is insoluble in water, has a high melting point, is a good conductor and is hard. Gold applies are all those statements.
Kbr is good soluble in water, and is a bad conductorbecause it is just a powder, and the molecules have no mobility, and therefore it cannot conduct electricity. The unknown substance is not Kbr.
The unknown substance is Au ( gold)
Answer:
(a) Tetrahedral;
(b) Bent
Explanation:
(a) I assume you meant either 
or 
. In both cases, we expect to have the same shape, however.
In phosphoric acid, the central atom, phosphorus, has a total of three single P-O bonds and one double P=O bond. No lone pairs are present. According to the VSEPR theory, the steric number is the sum of the bonds (ignoring multiplicity) and the lone pairs present on the central atom. For a total of 4 bonds and no lone pairs, the steric number of P is 4. This corresponds to a tetrahedral shape both electronically and geometrically. We don't expect any significant deviation, as no lone pairs are present on P, so we would have an angle of about 
.
(b) In the given ether, oxygen has two bonds. This leaves 2 lone pairs, so that we have an octet on oxygen. Similarly to (a), the steric number is 4. However, we have two lone pairs. This means we don't have a tetrahedral shape anymore, the molecule is bent with an angle of about 
. The angle is significantly reduced compared to the tetrahedal arrangement due to the presence of lone pairs that repel stronger than the shared electrons.
